覆盖Django ModelForm中的save方法
我无法覆盖ModelForm保存方法。这是我收到的错误:
Exception Type: TypeError Exception Value: save() got an unexpected keyword argument 'commit'
我的意图是让表单为3个字段提交许多值,然后为这些字段的每个组合创建一个对象,并保存每个对象。朝正确的方向发展将是王牌。
class CallResultType(models.Model): id = models.AutoField(db_column='icontact_result_code_type_id', primary_key=True)
callResult = models.ForeignKey('CallResult', db_column='icontact_result_code_id')
campaign = models.ForeignKey('Campaign', db_column='icampaign_id')
callType = models.ForeignKey('CallType', db_column='icall_type_id')
agent = models.BooleanField(db_column='bagent', default=True)
teamLeader = models.BooleanField(db_column='bTeamLeader', default=True)
active = models.BooleanField(db_column='bactive', default=True)
from django.forms import ModelForm, ModelMultipleChoiceFieldfrom callresults.models import *
class CallResultTypeForm(ModelForm):
callResult = ModelMultipleChoiceField(queryset=CallResult.objects.all())
campaign = ModelMultipleChoiceField(queryset=Campaign.objects.all())
callType = ModelMultipleChoiceField(queryset=CallType.objects.all())
def save(self, force_insert=False, force_update=False):
for cr in self.callResult:
for c in self.campain:
for ct in self.callType:
m = CallResultType(self) # this line is probably wrong
m.callResult = cr
m.campaign = c
m.calltype = ct
m.save()
class Meta:
model = CallResultType
class CallResultTypeAdmin(admin.ModelAdmin): form = CallResultTypeForm
回答:
在你里面save
你必须有论点commit
。如果有任何内容覆盖你的表单,或者想要修改其保存的内容,它将执行操作save(commit=False)
,修改输出,然后将其保存。
另外,你的ModelForm应该返回它保存的模型。通常,ModelForm的save
外观类似于:
def save(self, commit=True): m = super(CallResultTypeForm, self).save(commit=False)
# do custom stuff
if commit:
m.save()
return m
最后,由于你访问事物的方式,许多ModelForm都无法使用。相反self.callResult
,你需要使用self.fields['callResult']
。
更新:针对你的回答:
旁:为什么不在ManyToManyField
Model中使用s而不用这样做呢?似乎你正在存储冗余数据并为自己(和我:P
)做更多的工作。
from django.db.models import AutoField def copy_model_instance(obj):
"""
Create a copy of a model instance.
M2M relationships are currently not handled, i.e. they are not copied. (Fortunately, you don't have any in this case)
See also Django #4027. From http://blog.elsdoerfer.name/2008/09/09/making-a-copy-of-a-model-instance/
"""
initial = dict([(f.name, getattr(obj, f.name)) for f in obj._meta.fields if not isinstance(f, AutoField) and not f in obj._meta.parents.values()])
return obj.__class__(**initial)
class CallResultTypeForm(ModelForm):
callResult = ModelMultipleChoiceField(queryset=CallResult.objects.all())
campaign = ModelMultipleChoiceField(queryset=Campaign.objects.all())
callType = ModelMultipleChoiceField(queryset=CallType.objects.all())
def save(self, commit=True, *args, **kwargs):
m = super(CallResultTypeForm, self).save(commit=False, *args, **kwargs)
results = []
for cr in self.callResult:
for c in self.campain:
for ct in self.callType:
m_new = copy_model_instance(m)
m_new.callResult = cr
m_new.campaign = c
m_new.calltype = ct
if commit:
m_new.save()
results.append(m_new)
return results
允许继承CallResultTypeForm
,以防万一。
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