仅使用bash /标准Linux命令去除字符串中的单引号和双引号

  • Z时代
  • 2024-01-10
  • 分类：问答

我正在寻找仅使用bash /标准Linux命令即可将字符串转换为以下内容的东西：

  1. Single-quotes surrounding a string should be removed

  2. Double-quotes surrounding a string should be removed

  3. Unquoted strings should remain the same

  4. Strings with unmatched surrounding quotes should remain the same

  5. Single-quotes that don’t surround the string should remain

  6. Double-quotes that don’t surround the string should remain

例如：

  • ‘Food’ should become Food

  • “Food” should become Food

  • Food should remain the same

  • ‘Food” should remain the same

  • “Food’ should remain the same

  • ‘Fo’od’ should become Fo’od

  • “Fo’od” should become Fo’od

  • Fo’od should remain the same

  • ‘Fo”od’ should become Fo”od

  • “Fo”od” should become Fo”od

  • Fo”od should remain the same

Thank you!

回答：

应该这样做：

sed "s/^\([\"']\)\(.*\)\1\$/\2/g" in.txt

其中in.txt是：

"Fo'od'
'Food'
"Food"
"Fo"od'
Food
'Food"
"Food'
'Fo'od'
"Fo'od"
Fo'od
'Fo"od'
"Fo"od"
Fo"od

而Expected.txt是：

"Fo'od'
Food
Food
"Fo"od'
Food
'Food"
"Food'
Fo'od
Fo'od
Fo'od
Fo"od
Fo"od
Fo"od

您可以检查它们是否符合：

diff -s <(sed "s/^\([\"']\)\(.*\)\1\$/\2/g" in.txt) expected.txt

以上是 仅使用bash /标准Linux命令去除字符串中的单引号和双引号 的全部内容， 来源链接： utcz.com/qa/427791.html

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