使用的SELECT语句具有不同数量的列(REDUX !!)

那里还有另一个与此类似的问题,但似乎并没有回答 我的 问题。

我的问题是这样的:为什么我ERROR 1222 (21000): The used SELECT statements have a different

number of columns要从下面的SQL中找回此错误?

SELECT * FROM friends

LEFT JOIN users AS u1 ON users.uid = friends.fid1

LEFT JOIN users AS u2 ON users.uid = friends.fid2

WHERE (friends.fid1 = 1) AND (friends.fid2 > 1)

UNION SELECT fid2 FROM friends

WHERE (friends.fid2 = 1) AND (friends.fid1 < 1)

ORDER BY RAND()

LIMIT 6;

这里是users

+------------+---------------+------+-----+---------+----------------+

| Field | Type | Null | Key | Default | Extra |

+------------+---------------+------+-----+---------+----------------+

| uid | int(11) | NO | PRI | NULL | auto_increment |

| first_name | varchar(50) | NO | | NULL | |

| last_name | varchar(50) | NO | | NULL | |

| email | varchar(128) | NO | UNI | NULL | |

| mid | varchar(40) | NO | | NULL | |

| active | enum('N','Y') | NO | | NULL | |

| password | varchar(64) | NO | | NULL | |

| sex | enum('M','F') | YES | | NULL | |

| created | datetime | YES | | NULL | |

| last_login | datetime | YES | | NULL | |

| pro | enum('N','Y') | NO | | NULL | |

+------------+---------------+------+-----+---------+----------------+

这里是friends

+---------------+--------------------------------------+------+-----+---------+----------------+

| Field | Type | Null | Key | Default | Extra |

+---------------+--------------------------------------+------+-----+---------+----------------+

| friendship_id | int(11) | NO | MUL | NULL | auto_increment |

| fid1 | int(11) | NO | PRI | NULL | |

| fid2 | int(11) | NO | PRI | NULL | |

| status | enum('pending','accepted','ignored') | NO | | NULL | |

+---------------+--------------------------------------+------+-----+---------+----------------+

如果您也想对这里发生的任何疯狂事情提供任何反馈,请随时这样做。我会结成小块。

回答:

UNION(UNIONUNION ALL)要求所有UNION查询必须具有:

  1. SELECT子句中的列数相同
  2. 列数据类型必须在每个位置都匹配

您的查询有:

SELECT f.*, u1.*, u2.* ...

UNION

SELECT fid2 FROM friends

我最简单的重写是:

   SELECT f.*, u.*

FROM FRIENDS AS f

JOIN USERS AS u ON u.uid = f.fid2

WHERE f.fid1 = 1

AND f.fid2 > 1

UNION

SELECT f.*, u.*

FROM FRIENDS AS f

JOIN USERS AS u ON u.uid = f.fid1

WHERE f.fid2 = 1

AND f.fid1 < 1

ORDER BY RAND()

LIMIT 6;

您已经USERS两次加入表,但似乎没有使用该信息。

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