selenium-python。如何捕获网络流量的响应

  • Z时代
  • 2024-01-10
  • 分类：问答

我正在使用pythonDjango创建一个Web应用程序。我正在使用selenium来启动无头浏览器（phantomjs）并单击几次，直到到达特定页面。我希望捕获网络流量并获得特定网络呼叫的响应。该网络调用实际上包含一个html文档作为其响应。

有什么办法可以做到这一点？

回答：

您可以访问浏览器或chromedriver日志，它们在网络响应方面略有不同。称为浏览器日志，称为performance驱动程序日志driver。它们返回一个类似json的对象，您可以解析该对象以使用其中的Network方法提取事件：

{'level': 'INFO',
  'message': '{"message":{"method":"Page.frameStoppedLoading","params":{"frameId":"FB10764A3ABF7FFC83110C39C5F7BF77"}},"webview":"C2D13BD13CF743B6D0695B35E9CC935C"}',
  'timestamp': 1538607113832},
 {'level': 'INFO',
  'message': '{"message":{"method":"Page.frameDetached","params":{"frameId":"FB10764A3ABF7FFC83110C39C5F7BF77"}},"webview":"C2D13BD13CF743B6D0695B35E9CC935C"}',
  'timestamp': 1538607113838},
 {'level': 'INFO',
  'message': '{"message":{"method":"Network.requestWillBeSent","params":{"documentURL":"https://stackoverflow.com/questions/52633697/selenium-python-how-to-capture-network-traffics-response","frameId":"C2D13BD13CF743B6D0695B35E9CC935C","hasUserGesture":false,"initiator":{"type":"other"},"loaderId":"5331BFDC4F466FCED920CFC9F033D2EC","request":{"headers":{"Upgrade-Insecure-Requests":"1","User-Agent":"Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36"},"initialPriority":"VeryHigh","method":"GET","mixedContentType":"none","referrerPolicy":"no-referrer-when-downgrade","url":"https://stackoverflow.com/questions/52633697/selenium-python-how-to-capture-network-traffics-response"},"requestId":"5331BFDC4F466FCED920CFC9F033D2EC","timestamp":104499.729,"type":"Document","wallTime":1538607113.838206}},"webview":"C2D13BD13CF743B6D0695B35E9CC935C"}',
  'timestamp': 1538607113839},...}

您需要启用登录DesiredCapabilities，然后使用JSON模块进行解析：

import json
from selenium import webdriver
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
caps = DesiredCapabilities.CHROME
caps['loggingPrefs'] = {'performance': 'ALL'}
driver = webdriver.Chrome(desired_capabilities=caps)
driver.get('https://stackoverflow.com/questions/52633697/selenium-python-how-to-capture-network-traffics-response')
def process_browser_log_entry(entry):
    response = json.loads(entry['message'])['message']
    return response
browser_log = driver.get_log('performance') 
events = [process_browser_log_entry(entry) for entry in browser_log]
events = [event for event in events if 'Network.response' in event['method']]

我不知道是否可以使用此方法访问响应数据本身，但是可以获取响应的URL。

以上是 selenium-python。如何捕获网络流量的响应 的全部内容， 来源链接： utcz.com/qa/420208.html

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