如何使用Pygame创建文本输入框？
我想在Python中从用户那里获取一些文本输入，并在文本框中显示他们正在输入的内容，然后当他们按Enter时，它将存储在字符串中。
我到处都看过，但是什么也找不到。我正在使用Pygame。
回答：
您可以将rect定义为输入框的区域。如果发生pygame.MOUSEBUTTONDOWN事件，请使用rectcolliderect方法input_box检查它是否与冲突，event.pos然后通过将active变量设置为来激活它True。
如果该框处于活动状态，则可以键入一些内容，Pygame将生成pygame.KEYDOWN事件，该事件具有unicode可以简单地添加到字符串中的属性，例如text
+= event.unicode。如果用户按下Enter键，则可以对text字符串进行操作（在示例中，我只是打印该字符串）并将其重置为''。
import pygame as pgdef main():
screen = pg.display.set_mode((640, 480))
font = pg.font.Font(None, 32)
clock = pg.time.Clock()
input_box = pg.Rect(100, 100, 140, 32)
color_inactive = pg.Color('lightskyblue3')
color_active = pg.Color('dodgerblue2')
color = color_inactive
active = False
text = ''
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
if event.type == pg.MOUSEBUTTONDOWN:
# If the user clicked on the input_box rect.
if input_box.collidepoint(event.pos):
# Toggle the active variable.
active = not active
else:
active = False
# Change the current color of the input box.
color = color_active if active else color_inactive
if event.type == pg.KEYDOWN:
if active:
if event.key == pg.K_RETURN:
print(text)
text = ''
elif event.key == pg.K_BACKSPACE:
text = text[:-1]
else:
text += event.unicode
screen.fill((30, 30, 30))
# Render the current text.
txt_surface = font.render(text, True, color)
# Resize the box if the text is too long.
width = max(200, txt_surface.get_width()+10)
input_box.w = width
# Blit the text.
screen.blit(txt_surface, (input_box.x+5, input_box.y+5))
# Blit the input_box rect.
pg.draw.rect(screen, color, input_box, 2)
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
pg.init()
main()
pg.quit()
这是一个面向对象的变体，使您可以轻松创建多个输入框：
import pygame as pgpg.init()
screen = pg.display.set_mode((640, 480))
COLOR_INACTIVE = pg.Color('lightskyblue3')
COLOR_ACTIVE = pg.Color('dodgerblue2')
FONT = pg.font.Font(None, 32)
class InputBox:
def __init__(self, x, y, w, h, text=''):
self.rect = pg.Rect(x, y, w, h)
self.color = COLOR_INACTIVE
self.text = text
self.txt_surface = FONT.render(text, True, self.color)
self.active = False
def handle_event(self, event):
if event.type == pg.MOUSEBUTTONDOWN:
# If the user clicked on the input_box rect.
if self.rect.collidepoint(event.pos):
# Toggle the active variable.
self.active = not self.active
else:
self.active = False
# Change the current color of the input box.
self.color = COLOR_ACTIVE if self.active else COLOR_INACTIVE
if event.type == pg.KEYDOWN:
if self.active:
if event.key == pg.K_RETURN:
print(self.text)
self.text = ''
elif event.key == pg.K_BACKSPACE:
self.text = self.text[:-1]
else:
self.text += event.unicode
# Re-render the text.
self.txt_surface = FONT.render(self.text, True, self.color)
def update(self):
# Resize the box if the text is too long.
width = max(200, self.txt_surface.get_width()+10)
self.rect.w = width
def draw(self, screen):
# Blit the text.
screen.blit(self.txt_surface, (self.rect.x+5, self.rect.y+5))
# Blit the rect.
pg.draw.rect(screen, self.color, self.rect, 2)
def main():
clock = pg.time.Clock()
input_box1 = InputBox(100, 100, 140, 32)
input_box2 = InputBox(100, 300, 140, 32)
input_boxes = [input_box1, input_box2]
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
for box in input_boxes:
box.handle_event(event)
for box in input_boxes:
box.update()
screen.fill((30, 30, 30))
for box in input_boxes:
box.draw(screen)
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
main()
pg.quit()
也有第三方模块可用，例如pygame_textinput。
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