在与ES6深度嵌套的对象的javascript数组中寻找价值

在对象数组中,我需要找到value-- keyactivity:但是,activitykey可以将其深深地嵌套在数组中,如下所示:

const activityItems = [

{

name: 'Sunday',

items: [

{

name: 'Gym',

activity: 'weights',

},

],

},

{

name: 'Monday',

items: [

{

name: 'Track',

activity: 'race',

},

{

name: 'Work',

activity: 'meeting',

},

{

name: 'Swim',

items: [

{

name: 'Beach',

activity: 'scuba diving',

},

{

name: 'Pool',

activity: 'back stroke',

},

],

},

],

},

{} ...

{} ...

];

因此,我编写了一个递归算法来确定数组中是否存在某个活动:

let match = false;

const findMatchRecursion = (activity, activityItems) => {

for (let i = 0; i < activityItems.length; i += 1) {

if (activityItems[i].activity === activity) {

match = true;

break;

}

if (activityItems[i].items) {

findMatchRecursion(activity, activityItems[i].items);

}

}

return match;

};

有没有ES6办法确定活动是否存在于像这样的数组中?

我尝试过这样的事情:

const findMatch(activity, activityItems) {

let obj = activityItems.find(o => o.items.activity === activity);

return obj;

}

但这不适用于深层嵌套的活动。

谢谢

回答:

您可以使用some()方法和递归来查找活动是否存在于任何级别并返回true / false作为结果。

const activityItems = [{"name":"Sunday","items":[{"name":"Gym","activity":"weights"}]},{"name":"Monday","items":[{"name":"Track","activity":"race"},{"name":"Work","activity":"meeting"},{"name":"Swim","items":[{"name":"Beach","activity":"scuba diving"},{"name":"Pool","activity":"back stroke"}]}]}]

let findDeep = function(data, activity) {

return data.some(function(e) {

if(e.activity == activity) return true;

else if(e.items) return findDeep(e.items, activity)

})

}

console.log(findDeep(activityItems, 'scuba diving'))

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