如何在JPA EntityManager查询上设置超时期限

  • Z时代
  • 2024-01-10
  • 分类：问答

我目前从EntityManager查询中收到连接超时错误。是否可以为这些设置超时？

persistence.xml

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
  <persistence-unit name="CallPU" transaction-type="RESOURCE_LOCAL">
    <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
    <class>call.structure.Task</class>
    <class>call.structure.Installation</class>
    <class>call.structure.Contents</class>
    <class>call.structure.Recipient</class>
    <class>call.structure.CallTask</class>
    <class>call.structure.SmsTask</class>
    <class>call.structure.EmailTask</class>
    <class>call.security.User</class>
    <class>call.structure.content.Content</class>
    <class>call.structure.content.RecordContent</class>
    <class>call.structure.content.WaitContent</class>
    <class>call.structure.content.TextContent</class>
    <class>call.structure.content.VariableContent</class>
    <class>call.structure.content.SoundContent</class>
    <class>call.structure.content.SubjectContent</class>
    <class>call.structure.content.FileContent</class>
    <class>call.structure.Bounce</class>
    <properties>
      <property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@127.0.0.1:1521:TEST"/>
      <property name="javax.persistence.jdbc.password" value="userpassword"/>
      <property name="javax.persistence.jdbc.driver" value="oracle.jdbc.OracleDriver"/>
      <property name="javax.persistence.jdbc.user" value="username"/>
    </properties>
   </persistence-unit>
</persistence>

代码在我的线程的运行功能中超时：

private class TaskDB extends Thread {
    private final long WAITING_TIME = 20000L;
    @Override
    public void run() {
        Set<SmsTask> remove = SMSManager.this.getRemoveTask();
        Set<SmsTask> normal = SMSManager.this.getNormalTask();
        try {
            while(true){
                EntityManager em = DB.getEM();  //Calls EntityManagerFactory.createEntityManager()
                em.getTransaction().begin();
                Set<SmsTask> normalClone = new HashSet<SmsTask>(normal);
                // Abort task in futur.
                List<SmsTask> taskToRemove = new ArrayList<SmsTask>();
                if (!remove.isEmpty()) {
                    String queryString = "SELECT t FROM SmsTask t WHERE t.id IN :remove ";
                    if (!normalClone.isEmpty())
                        queryString += "AND t.id NOT IN :normal ";
                    Query query = em.createQuery(queryString);
                    query.setParameter("remove", Utils.taskToIdList(remove));
                    if (!normalClone.isEmpty())
                        query.setParameter("normal", Utils.taskToIdList(normalClone));
                    taskToRemove = (List<SmsTask>) query.getResultList();
                    for (SmsTask task : taskToRemove) {
                        removedTask.add(task);
                        remove.remove(task);
                    }
                }
                String queryString = "SELECT t FROM SmsTask t WHERE (t.scheduleTime IS NULL OR t.scheduleTime < :dateNow) AND t.status = co.dium.call.structure.Task.StatusTask.NOT_START ";
                if (!taskToRemove.isEmpty())
                    queryString += "AND t.id NOT IN :toRemove ";
                Query query = em.createQuery(queryString);
                query.setParameter("dateNow", Utils.obtainUniversalTime());
                if (!taskToRemove.isEmpty())
                    query.setParameter("toRemove", Utils.taskToIdList(taskToRemove));
                List<SmsTask> taskResults = (List<SmsTask>) query.getResultList();
                em.getTransaction().commit();
                for (SmsTask task : taskResults) 
                    addTask(task);
                SMSManager.TaskRemove.sleep(WAITING_TIME);
            }
        } catch (InterruptedException ex) {
            Logger.getLogger(SMSManager.class.getName()).log(Level.SEVERE, null, ex);
        }
        System.out.println("Thread interrompu !");
        Thread.currentThread().interrupt();
    }
}

我收到的超时错误：

org.clipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLRecoverableException: I/O error: Socket read timed out
Error Code: 17002
Call: [....sql query...]
[...]
at org.eclipse.persistence.internal.EJBQueryImpl.getResultList(EJBQueryImpl.java:742)
at call.manager.sms.SMSManager$TaskDB.run(SMSManager.java:367)
Caused by: java.sql.SQLRecoverableException: I/O Error: Scoket read timed out
[...]

回答：

是的，那里有 javax.persistence.query.timeout 。根据JPA 2.0规范，对此查询提示的支持是可选的：

可移植应用程序不应依赖此提示。根据使用的持久性提供程序和数据库，可能会或可能不会观察到提示。

可以将所有查询的默认值（以毫秒为单位）设置为persistence.xml：

<property name="javax.persistence.query.timeout" value="1000"/>

通过持久性创建EntityManagerFactory时，也可以赋予相同的属性。createEntityManagerFactory。

每个查询也可以覆盖/设置它：

query.setHint("javax.persistence.query.timeout", 2000);

可以通过NamedQuery中的属性提示获得相同的功能。

以上是 如何在JPA EntityManager查询上设置超时期限 的全部内容， 来源链接： utcz.com/qa/410712.html

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