如何将grobs存储在列表中并将它们传递给grobTree（）？

让我们试着回答写下来的问题。这个问题，因为我读它去如下：

此代码：

grobs <- grobTree(
    gp = gpar(fontsize = 14, fontface = 'bold'), 
    textGrob(label = title_segments[1], name = "title1", 
      x = unit(2.33 - nudge_x, "lines"), 
      y = unit(-.5, "lines"), 
      hjust = 0, vjust = 0, gp = gpar(col = colors[1])), 
    if(length(title_segments) > 1){ 
    textGrob(label = title_segments[2], name = "title2", 
      x = grobWidth("title1") + unit(2.24 - nudge_x, "lines"), 
      y = unit(-.5, "lines"), 
      hjust = 0, vjust = 0, gp = gpar(col = colors[2])) 
    }, 
    if(length(title_segments) > 2){ 
    textGrob(label = title_segments[3], name = "title3", 
      x = grobWidth("title1") + grobWidth("title2") + unit(2.24 - nudge_x, "lines"), 
      y = unit(-.5, "lines"), 
      hjust = 0, vjust = 0, gp = gpar(col = colors[3])) 
    }, 
    if(length(title_segments) > 3){ 
    textGrob(label = title_segments[4], name = "title4", 
      x = grobWidth("title1") + grobWidth("title2") + grobWidth("title3") + unit(2.24 - nudge_x, "lines"), 
      y = unit(-.5, "lines"), 
      hjust = 0, vjust = 0, gp = gpar(col = colors[4])) 
    }, 
    if(length(title_segments) > 4){ 
    textGrob(label = title_segments[5], name = "title5", 
      x = grobWidth("title1") + grobWidth("title2") + grobWidth("title3") + grobWidth("title4") + unit(2.24 - nudge_x, "lines"), 
      y = unit(-.5, "lines"), 
      hjust = 0, vjust = 0, gp = gpar(col = colors[5])) 
    } 
) 

但是，此代码，这意味着对以前的代码的计算消遣，并不：

grobs <- NULL 
grobs[1] <- list(gp = gpar(fontsize = 14, fontface = 'bold')) 
grobs[2] <- list(textGrob(label = title_segments[1], name = "title1", 
          x = unit(2.33 - nudge_x, "lines"), 
          y = unit(-.5, "lines"), 
          hjust = 0, vjust = 0, gp = gpar(col = colors[1]))) 
if(length(title_segments) > 1){ 
    x <- unit(2.24 - nudge_x, "lines") 
    more_grobs <- pmap(list(title_segments[-1], colors[-1], 
seq_along(title_segments)[-1]), function(segment, color, i){ 
    grob <- textGrob(label = segment, name = paste0('title', i, sep = ''), 
          x = x + grobWidth(paste0('title', i - 1, sep = '')),  
          y = unit(-.5, "lines"), 
          hjust = 0, vjust = 0, gp = gpar(col = color)) 
    }) 
} 
grobs <- c(grobs, more_grobs) 
grobs <- do.call(what = grobTree, args = grobs) ### ERROR HERE 

发生了什么事？答案是，问题出在了前两行：

grobs <- NULL 
grobs[1] <- list(gp = gpar(fontsize = 14, fontface = 'bold')) 

分配grobs[1] <-消除了gp = ...命名为列表元素，因此该功能grobTree()不明白的是，第一个参数是不是一个GROB 。修复很简单。将这两行替换为：

grobs <- list(gp = gpar(fontsize = 14, fontface = 'bold')) 

现在工作正常，有点。 do.call()行不会导致错误了。但是，单词的间距仍然不正确，因为pmap()调用不会创建从第1个到第n个所有grob宽度的总和。相反，它只使用前一个grob的grob宽度。此问题最好用一个递归函数解决，我认为：

make_grobs <- function(words, colors, x, y, hjust = 0, vjust = 0, i = 0) { 
    n <- length(words) 
    colors <- rep_len(colors, n) 
    name <- paste0('title', i) 
    grob <- textGrob(label = words[1], name = name, 
        x = x, y = y, hjust = hjust, vjust = vjust, 
        gp = gpar(col = colors[1])) 
    if (n == 1) { 
    list(grob) 
    } 
    else { 
    c(list(grob), 
     make_grobs(words[-1], colors[-1], 
       x + grobWidth(grob), y, hjust, vjust, i + 1)) 
    } 
} 

通过这个函数时，整个再现的示例变为：

library(purrr) 
library(grid) 
library(gridExtra) 
library(ggplot2) 
title_segments <- c('Help ', 'me ', 'please', '!') 
colors <- c('red', 'orange', 'green', 'blue') 
nudge_x = 0 
grobs <- do.call(what = grobTree, 
       args = c(make_grobs(title_segments, colors, 
            x = unit(2.33 - nudge_x, "lines"), 
            y = unit(-.5, "lines")), 
          list(gp = gpar(fontsize = 14, fontface = 'bold')))) 
qplot(displ, year, data = mpg) 
gb <- ggplot_build(last_plot()) 
gt <- ggplot_gtable(gb) 
gt$layout$clip[gt$layout$name=="panel"] <- "off" 
gg <- arrangeGrob(gt, top = grobs, padding = unit(2.6, "line")) 
grid.newpage() 
grid.draw(gg)