使用带有mysql查询结果的php获取父级下的所有子级,孙级等节点
我一直在试图解决这个问题,但是我什么都没走,希望有人可以救我。
我的问题是我正在使用邻接列表数据模型在mysql中生成我的层次结构数据。我可以将表(见下文)检索到多维数组中,并且每个项目都具有关联数组。我想要做的就是一旦得到这个数组,我想得到另一个数组,其所有节点(子,孙等)都位于父ID(包括父项)下。我只是无法锻炼如何在其中编写代码的PHP。
在MySQL中,我的表如下所示:
id name parent_id1 Electronics 0
2 Televisions 1
3 Portable Electronics 1
4 Tube 2
5 LCD 2
6 Plasma 2
7 Mp3 Players 3
8 CD Players 3
9 2 Way Radios 3
10 Flash 7
我可以使用此代码将所有行检索到与此相关的数组中。
$r = mysql_query("SELECT * FROM test "); $data = array();
while($row = mysql_fetch_assoc($r)) {
$data[] = $row;
}
获得结果:
Array (
[0] => Array
(
[id] => 1
[name] => Electronics
[parent_id] => 0
)
[1] => Array
(
[id] => 2
[name] => Televisions
[parent_id] => 1
)
[2] => Array
(
[id] => 3
[name] => Portable Electronics
[parent_id] => 1
)
[3] => Array
(
[id] => 4
[name] => Tube
[parent_id] => 2
)
[4] => Array
(
[id] => 5
[name] => LCD
[parent_id] => 2
)
[5] => Array
(
[id] => 6
[name] => Plasma
[parent_id] => 2
)
[6] => Array
(
[id] => 7
[name] => Mp3 Players
[parent_id] => 3
)
[7] => Array
(
[id] => 8
[name] => CD Players
[parent_id] => 3
)
[8] => Array
(
[id] => 9
[name] => 2 Way Radios
[parent_id] => 3
)
[9] => Array
(
[id] => 10
[name] => Flash
[parent_id] => 7
)
)
有了这些结果,我想用一个ID将其过滤掉。
举例来说,我想要便携式电子设备下每个节点的ID为3的关联数组。(使用ID作为代码)
它将返回一个包含ID为行的数组:
- 3便携式电子产品(必须包括选定的母体)
- 7 Mp3播放器(儿童)
- 8个CD播放器(儿童)
- 9 2路收音机(儿童)
- 10 Flash(大孩子)
如果Flash有孩子,它将也返回那些孩子。
因此,最终结果将返回与上面的数组类似的数组,但是仅包含那些项。
希望这可以帮助
提前致谢
回答:
回答:
之前,我曾发布过一种解决方案,可以从您提供的输出中构建多维数组,以及一种id
从特定数组中获取特定子元素的方法。现在,我已经弄清楚了如何直接从输出中检索子元素(而不必首先通过一个buildtree()
函数:
function fetch_recursive($src_arr, $currentid, $parentfound = false, $cats = array()){
foreach($src_arr as $row)
{
if((!$parentfound && $row['id'] == $currentid) || $row['parent_id'] == $currentid)
{
$rowdata = array();
foreach($row as $k => $v)
$rowdata[$k] = $v;
$cats[] = $rowdata;
if($row['parent_id'] == $currentid)
$cats = array_merge($cats, fetch_recursive($src_arr, $row['id'], true));
}
}
return $cats;
}
要使用上面的函数,只需将输出数组传递$data
给第一个参数,然后id
您要从第二个参数中检索子元素:
例如:
$list = fetch_recursive($data, 3);
哪个应该为您提供正确的数组结构id
3
(如该答案最后一个代码框中的示例所示)。
到目前为止,我从来没有写过一个递归函数来从此设计中构建嵌套树。我敢肯定还有很多其他人编写了类似的函数,但是这个绝对可以为您工作:
function buildtree($src_arr, $parent_id = 0, $tree = array()){
foreach($src_arr as $idx => $row)
{
if($row['parent_id'] == $parent_id)
{
foreach($row as $k => $v)
$tree[$row['id']][$k] = $v;
unset($src_arr[$idx]);
$tree[$row['id']]['children'] = buildtree($src_arr, $row['id']);
}
}
ksort($tree);
return $tree;
}
此函数将在邻接表之外递归地构建树,并保持ID的升序排列。这也使id
每个父/子的成为每个信息数组的键。
这段代码:
$r = mysql_query("SELECT * FROM test ");$data = array();
while($row = mysql_fetch_assoc($r)) {
$data[] = $row;
}
echo '<pre>';
print_r(buildtree($data));
echo '</pre>';
将输出如下内容:
Array (
[1] => Array
(
[id] => 1
[name] => Electronics
[parent_id] => 0
[children] => Array
(
[2] => Array
(
[id] => 2
[name] => Televisions
[parent_id] => 1
[children] => Array
(
[4] => Array
(
[id] => 4
[name] => Tube
[parent_id] => 2
[children] => Array()
)
[5] => Array
(
[id] => 5
[name] => LCD
[parent_id] => 2
[children] => Array()
)
[6] => Array
(
[id] => 6
[name] => Plasma
[parent_id] => 2
[children] => Array()
)
)
)
[3] => Array
(
[id] => 3
[name] => Portable Electronics
[parent_id] => 1
[children] => Array
(
[7] => Array
(
[id] => 7
[name] => Mp3 Players
[parent_id] => 3
[children] => Array
(
[10] => Array
(
[id] => 10
[name] => Flash
[parent_id] => 7
[children] => Array()
)
)
)
[8] => Array
(
[id] => 8
[name] => CD Players
[parent_id] => 3
[children] => Array()
)
[9] => Array
(
[id] => 9
[name] => 2 Way Radios
[parent_id] => 3
[children] => Array()
)
)
)
)
)
)
要将特定对象的所有子节点放入id
一维数组中,可以使用以下函数:
function fetch_recursive($tree, $parent_id, $parentfound = false, $list = array()){
foreach($tree as $k => $v)
{
if($parentfound || $k == $parent_id)
{
$rowdata = array();
foreach($v as $field => $value)
if($field != 'children')
$rowdata[$field] = $value;
$list[] = $rowdata;
if($v['children'])
$list = array_merge($list, fetch_recursive($v['children'], $parent_id, true));
}
elseif($v['children'])
$list = array_merge($list, fetch_recursive($v['children'], $parent_id));
}
return $list;
}
基于上面的buildtree()
函数,假设我们要获取所有id
3 个子节点:
echo '<pre>';print_r(fetch_recursive(buildtree($a), 3));
echo '</pre>';
这将输出:
Array(
[0] => Array
(
[id] => 3
[name] => Portable Electronics
[parent_id] => 1
)
[1] => Array
(
[id] => 7
[name] => Mp3 Players
[parent_id] => 3
)
[2] => Array
(
[id] => 10
[name] => Flash
[parent_id] => 7
)
[3] => Array
(
[id] => 8
[name] => CD Players
[parent_id] => 3
)
[4] => Array
(
[id] => 9
[name] => 2 Way Radios
[parent_id] => 3
)
)
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