如何遍历Hashmap中的元素？

  • Z时代
  • 2024-01-10
  • 分类：问答

我想做一个Java游戏。首先，程序要求玩家的数量。之后，它询问他们的名字。我将他们的名字放在HashMapID和分数中。在游戏结束时，我会计算分数，然后将其放在HashMap（特定名称的特定分数）中。有谁知道如何做到这一点？这是我的代码：

public class Player {
public Player() {
}
public void setScore(int score) {
    this.score = score;
}
public void setName(String name) {
    this.name = name;
}
private String name;
private int score;
public Player(String name, int score) {
    this.name = name;
    this.score = score;
}
 public String getName() { 
     return name;
 }
@Override
public String toString() {
    return "Player{" + "name=" + name + "score=" + score + '}';
}
public int getScore() {
    return score;
}

Scanner scanner = new Scanner(System.in);
HashMap<Integer,Player> name= new HashMap<Integer,Player>();
    System.out.printf("Give the number of the players ");
    int number_of_players = scanner.nextInt();
    for(int k=1;k<=number_of_players;k++)
     {
         System.out.printf("Give the name of player %d: ",k);
         name_of_players= scanner.nextLine();
         name.put(k, new Player(name_of_players,0));//k=id and 0=score
     }
   //This for finally returns the score and          
    for(int k=1;k<=number_of_players;k++)
  {  
      Player name1 = name.get(k);
     System.out.print("Name of player in this round:"+name1.getName());
    ..............
    .............
    int score=p.getScore();
    name.put(k,new Player(name1.getName(),scr));//I think here is the problem
    for(int n=1;n<=number_of_players;n++)//prints all the players with their score
      {
     System.out.print("The player"+name1.getName()+" has "+name1.getScore()+"points");
      }

有谁知道我最后如何打印，例如：

"The player Nick has 10 points.
 The player Mary has 0 points."

我主要是这样做的（正如Jigar Joshi建议的那样）

 name.put(k,new Player(name1.getName(),scr)); 
 Set<Map.Entry<Integer, Player>> set =   name.entrySet();
 for (Map.Entry<Integer, Player> me : set) 
 { 
 System.out.println("Score :"+me.getValue().getScore() +" Name:"+me.getValue().getName());
}

当我将球员的两个名字“ a”和“ b”放进去时，它会显示“分数：0名称：a分数：4名称：a”。我认为问题出在这里

 name.put(k,new Player(name1.getName(),scr));

如何将名称放在上一个的“ names_of_players”中for？

回答：

迭代中需要关键和价值

使用entrySet()迭代通过Map和需要访问值和键：

Map<String, Person> hm = new HashMap<String, Person>();
hm.put("A", new Person("p1"));
hm.put("B", new Person("p2"));
hm.put("C", new Person("p3"));
hm.put("D", new Person("p4"));
hm.put("E", new Person("p5"));
Set<Map.Entry<String, Person>> set = hm.entrySet();
for (Map.Entry<String, Person> me : set) {
  System.out.println("Key :"+me.getKey() +" Name : "+ me.getValue().getName()+"Age :"+me.getValue().getAge());
}

迭代中需要密钥

如果您只想遍历keys地图，可以使用keySet()

for(String key: map.keySet()) {
     Person value = map.get(key); 
}

迭代需要价值

如果您只想遍历values地图，可以使用values()

for(Person person: map.values()) {
}

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