使用单个查询(递归查询)在mysql表中查找所有父级

我有这个架构

| ID |             TITLE | CONTROLLER |            METHOD | PARENT_ID |

|----|-------------------|------------|-------------------|-----------|

| 1 | Dashboard | admin | dashboard | 0 |

| 2 | Content | admin | content | 0 |

| 3 | Modules | admin | modules | 0 |

| 4 | Users | admin | users | 0 |

| 5 | Settings | admin | settings | 0 |

| 6 | Reports | admin | reports | 0 |

| 7 | Help | admin | help | 0 |

| 8 | Pages | content | pages | 2 |

| 9 | Media | content | media | 2 |

| 10 | Articles | content | articles | 2 |

| 11 | Menues | content | menues | 2 |

| 12 | Templates | content | templates | 2 |

| 13 | Themes | content | themes | 2 |

| 14 | Blog | content | blog | 2 |

| 15 | Forum | content | forum | 2 |

| 16 | Core Modules | modules | core_module | 3 |

| 17 | User Modules | modules | user_module | 3 |

| 18 | All Users | users | all_users | 4 |

| 19 | Groups | users | groups | 4 |

| 20 | Permissions | users | permissions | 4 |

| 21 | Import and Export | users | import_export | 4 |

| 22 | Send Email | users | send_mail | 4 |

| 23 | Login Records | users | login_records | 4 |

| 24 | General Settings | settings | general_settings | 5 |

| 25 | Email Settings | settings | email_settings | 5 |

| 26 | Popular Content | reports | popular_content | 6 |

| 27 | Most Active Users | reports | most_active_users | 6 |

| 28 | Documentation | help | documentation | 7 |

| 29 | About | help | about | 7 |

| 30 | Products | products | product | 17 |

| 31 | Categories | categories | category | 17 |

SQL Fiddle演示。我已经插入了一些示例数据。

我需要找到唱片标题的所有父母Categories。如何仅通过一个查询就可以获取所有父母?

我的意思是我需要这个结果:

id | title        |  controller  | method      | url     | parent_id 

----------------------------------------------------------------

3 | Modules | admin | modules | (NULL) | 0

17 | User Modules | modules | user_module | (NULL) | 3

31 | Categories | categories | category | (NULL) | 17

假设我想使用其所有父项来获取条目,并且要使用where条件id = 31,那么它应该获取上述记录。

回答:

SELECT T2.id, T2.title,T2.controller,T2.method,T2.url

FROM (

SELECT

@r AS _id,

(SELECT @r := parent_id FROM menu WHERE id = _id) AS parent_id,

@l := @l + 1 AS lvl

FROM

(SELECT @r := 31, @l := 0) vars,

menu m

WHERE @r <> 0) T1

JOIN menu T2

ON T1._id = T2.id

ORDER BY T1.lvl DESC;

演示版

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