如何使用angularJS拦截器仅拦截特定的HTTP请求？

Z时代
2024-01-10
分类：问答

我知道如何拦截所有请求，但是我只想拦截来自我资源的请求。

有谁知道如何做到这一点？

services.config(['$httpProvider',function($httpProvider) {
    $httpProvider.interceptors.push('myHttpInterceptor');
}]);
services.factory("userPurchased", function ($resource) {
    return $resource("/api/user/purchases/:action/:item", 
        {}, 
        {
            'list': {method: 'GET', params: {action: 'list'}, isArray: false},
            'save': {method: 'PUT', params: {item: '@item'}},
            'remove': {method: 'DELETE', params: {item: '@item'}},
        }
    );
});
services.factory('myHttpInterceptor', function($q,$rootScope) {
    // $rootScope.showSpinner = false;
    return {
      response: function(response) {
        $rootScope.showSpinner = false;
        // do something on success
        console.log('success');
        console.log('status', response.status);
        //return response;
        return response || $q.when(response);
      },
     responseError: function(response) {
        // do something on error
        $rootScope.showSpinner = true;
        console.log('failure');
        console.log('status', response.status)
        //return response;
        return $q.reject(response);
      }
    };
  });

回答：

如果只想拦截来自特定资源的请求，则可以使用可选interceptor的$requestaction

属性。Angular的文档请参见此处（用法>操作）

angular.module('app', ['ngResource']).
  factory('resourceInterceptor', function() {
    return {
      response: function(response) {
        console.log('response intercepted: ', response);
      }
    }
  }).
  factory('resourceService', ['$resource', 'resourceInterceptor', function($resource, resourceInterceptor) {
    return $resource(":name", 
        {}, 
        {
            'list': {method: 'GET', isArray: false, interceptor: resourceInterceptor}
        }
    );
  }]).
  run(['resourceService', '$http', function(resourceService, $http) {
    resourceService.list({name: 'list.json'}); // <= intercepted
    $http.get('list.json'); // <= not intercepted
  }]);