MySQL删除重复记录但保持最新
我有独特的id
和email
领域。电子邮件被重复。我只想保留所有重复项的一个电子邮件地址,但保留最新的id
(最后插入的记录)。
我该如何实现?
回答:
假设您的表test
包含以下数据:
select id, email from test;
ID EMAIL
---------------------- --------------------
1 aaa
2 bbb
3 ccc
4 bbb
5 ddd
6 eee
7 aaa
8 aaa
9 eee
因此,我们需要找到所有重复的电子邮件并删除所有重复的电子邮件,但是最新的ID。
在这种情况下,aaa
,bbb
和eee
重复,所以我们要删除ID为1,7,2和6。
为此,首先我们需要查找所有重复的电子邮件:
select email from test
group by email
having count(*) > 1;
EMAIL
--------------------
aaa
bbb
eee
然后,从该数据集中,我们需要为这些重复的电子邮件中的每一封找到最新的ID:
select max(id) as lastId, email from test
where email in (
select email
from test
group by email
having count(*) > 1
)
group by email;
LASTID EMAIL
---------------------- --------------------
8 aaa
4 bbb
9 eee
最后,我们现在可以删除所有ID小于LASTID的电子邮件。因此解决方案是:
delete test from test
inner join (
select max(id) as lastId, email
from test
where email in (
select email
from test
group by email
having count(*) > 1
)
group by email
) duplic on duplic.email = test.email
where test.id < duplic.lastId;
我现在没有在这台机器上安装mySql,但是应该可以
回答:
上面的删除有效,但是我发现了一个更优化的版本:
delete test from test
inner join (
select max(id) as lastId, email
from test
group by email
having count(*) > 1) duplic on duplic.email = test.email
where test.id < duplic.lastId;
您会看到它删除了最旧的重复项,即1、7、2、6:
select * from test;+----+-------+
| id | email |
+----+-------+
| 3 | ccc |
| 4 | bbb |
| 5 | ddd |
| 8 | aaa |
| 9 | eee |
+----+-------+
另一个版本是Rene Limon删除的内容
delete from test where id not in (
select max(id)
from test
group by email)
以上是 MySQL删除重复记录但保持最新 的全部内容, 来源链接: utcz.com/qa/402845.html