生成int唯一ID作为android通知ID
当我发送多个推送通知时,我需要将它们全部显示在按发送desc的时间排序的通知栏中。我知道我应该使用唯一的通知-
我尝试生成随机数,但这不能解决我的问题,因为我需要对它们进行订购。我尝试使用AtomicInt
,但仍然没有得到想要的结果。
package com.mypackage.lebadagency;import java.util.concurrent.atomic.AtomicInteger;
import android.app.IntentService;
import android.app.Notification;
import android.app.NotificationManager;
import android.app.PendingIntent;
import android.content.Context;
import android.content.Intent;
import android.graphics.Color;
import android.os.Bundle;
import android.os.SystemClock;
import android.support.v4.app.NotificationCompat;
import android.util.Log;
import android.widget.RemoteViews;
import com.google.android.gms.gcm.GoogleCloudMessaging;
public class GCMNotificationIntentService extends IntentService {
private AtomicInteger c = new AtomicInteger(0);
public int NOTIFICATION_ID = c.incrementAndGet();
private NotificationManager mNotificationManager;
NotificationCompat.Builder builder;
public GCMNotificationIntentService() {
super("GcmIntentService");
}
public static final String TAG = "GCMNotificationIntentService";
@Override
protected void onHandleIntent(Intent intent) {
Bundle extras = intent.getExtras();
GoogleCloudMessaging gcm = GoogleCloudMessaging.getInstance(this);
String messageType = gcm.getMessageType(intent);
if (!extras.isEmpty()) {
if (GoogleCloudMessaging.MESSAGE_TYPE_SEND_ERROR
.equals(messageType)) {
sendNotification("Send error: " + extras.toString());
} else if (GoogleCloudMessaging.MESSAGE_TYPE_DELETED
.equals(messageType)) {
sendNotification("Deleted messages on server: "
+ extras.toString());
} else if (GoogleCloudMessaging.MESSAGE_TYPE_MESSAGE
.equals(messageType)) {
for (int i = 0; i < 3; i++) {
Log.i(TAG,
"Working... " + (i + 1) + "/5 @ "
+ SystemClock.elapsedRealtime());
try {
Thread.sleep(5000);
} catch (InterruptedException e) {
}
}
Log.i(TAG, "Completed work @ " + SystemClock.elapsedRealtime());
sendNotification(""
+ extras.get(Config.MESSAGE_KEY));
Log.i(TAG, "Received: " + extras.toString());
}
}
GcmBroadcastReceiver.completeWakefulIntent(intent);
}
private void sendNotification(String msg) {
Log.d(TAG, "Preparing to send notification...: " + msg);
mNotificationManager = (NotificationManager) this
.getSystemService(Context.NOTIFICATION_SERVICE);
//here start
Intent gcmintent = new Intent(this, AppGcmStation.class);
gcmintent.putExtra("ntitle", msg);
gcmintent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
int requestID = (int) System.currentTimeMillis();
//here end
PendingIntent contentIntent = PendingIntent.getActivity(this, requestID,
gcmintent, PendingIntent.FLAG_UPDATE_CURRENT);
NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(
this).setSmallIcon(R.drawable.ic_launcher)
.setContentTitle("my title")
.setStyle(new NotificationCompat.BigTextStyle().bigText(msg))
.setContentText(msg);
mBuilder.setAutoCancel(true);
mBuilder.setTicker(msg);
mBuilder.setVibrate(new long[] { 1000, 1000, 1000, 1000, 1000 });
mBuilder.setLights(Color.RED, 3000, 3000);
mBuilder.setContentIntent(contentIntent);
mBuilder.setDefaults(Notification.DEFAULT_SOUND);
mNotificationManager.notify(NOTIFICATION_ID, mBuilder.build());
Log.d(TAG, "Notification sent successfully.");
}
}
我需要最好和最简单的方法来生成一个int ID,该ID可以递增以将其分配为通知ID。
回答:
您为所有通知使用相同的通知ID(值始终为1)。您可能应该将通知ID分离到单独的单例类中:
public class NotificationID { private final static AtomicInteger c = new AtomicInteger(0);
public static int getID() {
return c.incrementAndGet();
}
}
然后在代码中使用NotificationID.getID()
代替NOTIFICATION_ID
。
编辑:正如@racs在评论中指出的那样,如果您的应用程序进程被杀死,上述方法不足以确保行为正确。至少AtomicInteger
应从某些活动的保存状态(而不是从0开始)初始化的初始值。如果通知ID在应用程序的重新启动期间需要唯一(同样,应用程序进程可能会被终止),则最新值应在每次增量后保存在某个位置(可能保存到共享首选项),并在应用启动时恢复。
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