Jersey ExceptionMapper不会映射异常

  • Z时代
  • 2024-01-10
  • 分类：问答

我的Spring Boot + Jersey REST服务无法正常工作。

EmailExistsException在UserController中引发，但我始终只收到错误500。而且我的异常未记录。

我怀疑异常处理存在一些配置问题，但不知道在哪里进行设置。有什么建议么？

@POST
@Path("register")
@Produces(MediaType.APPLICATION_JSON)
public Response register(NewUserPayload newUserPayload) throws EmailExistsException, MessagingException

EmailExistsExceptionMapper

@Provider
public class EmailExistsExceptionMapper extends AbstractExceptionMapper       implements
    ExceptionMapper<EmailExistsException>
{
@Override
public Response toResponse(EmailExistsException e)
{
    ResponseEntity re = new ResponseEntity(org.springframework.http.HttpStatus.BAD_REQUEST);
    return this.errorResponse(HttpStatus.BAD_REQUEST_400, re, e);
}
}

AbstractExceptionMapper

@Slf4j
public abstract class AbstractExceptionMapper
{
protected Response errorResponse(int status, ResponseEntity responseEntity, Throwable t)
{
    StringWriter sw = new StringWriter();
    PrintWriter pw = new PrintWriter(sw);
    t.printStackTrace(pw);
    log.error(sw.toString()); // logging stack trace.
    return customizeResponse(status, responseEntity);
}
private Response customizeResponse(int status, ResponseEntity responseEntity)
{
    return Response.status(status).entity(responseEntity).build();
}
}

build.gradle

compile("org.springframework.boot:spring-boot-starter-web") {
    exclude module: 'spring-boot-starter-tomcat'
}
compile "org.springframework.boot:spring-boot-starter-jetty"
compile "org.springframework.boot:spring-boot-starter-security"
compile "org.springframework.boot:spring-boot-starter-aop"
compile "org.springframework.boot:spring-boot-starter-data-jpa"
compile "org.springframework.boot:spring-boot-starter-thymeleaf"
compile "org.springframework.boot:spring-boot-starter-jersey"
compile 'org.springframework.boot:spring-boot-starter-mail'

回答：

解决了我的问题的答案：

我已经把packages（“ package.name”）; 这是我的根程序包名称，异常映射器的工作原理很吸引人。

@Component
@ApplicationPath("/api")
public class JerseyConfig extends ResourceConfig
{
public JerseyConfig()
{
    packages("package.name");
    register(UserController.class);
    register(TimezoneController.class);
}
}

以上是 Jersey ExceptionMapper不会映射异常 的全部内容， 来源链接： utcz.com/qa/400562.html

回到顶部