用sax跳过节点

  • Z时代
  • 2024-01-10
  • 分类：问答

解析时是否可以跳过节点，这skippedEntity与它有什么关系？

考虑以下XML：

<?xml version="1.0"?>
<nutrition>
<daily-values>
    <total-fat units="g">65</total-fat>
    <saturated-fat units="g">20</saturated-fat>
    <cholesterol units="mg">300</cholesterol>
    <sodium units="mg">2400</sodium>
    <carb units="g">300</carb>
    <fiber units="g">25</fiber>
    <protein units="g">50</protein>
</daily-values>
</nutrition>

我想跳过“钠”元素

回答：

您可以执行以下操作：

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.XMLReader;
public class Demo {
    public static void main(String[] args) throws Exception {
        SAXParserFactory spf = SAXParserFactory.newInstance();
        SAXParser sp = spf.newSAXParser();
        XMLReader xr = sp.getXMLReader();
        xr.setContentHandler(new MyContentHandler(xr));
        xr.parse("input.xml");
    }
}

MyContentHandler

此类负责处理您的XML文档。击中要忽略的节点时，可以在IgnoringContentHandler中进行交换，这将吞噬该节点的所有事件。

import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.XMLReader;
import org.xml.sax.helpers.DefaultHandler;
public class MyContentHandler extends DefaultHandler {
    private XMLReader xmlReader;
    public MyContentHandler(XMLReader xmlReader) {
        this.xmlReader = xmlReader;
    }
    public void startElement(String uri, String localName, String qName,
            Attributes atts) throws SAXException {
        if ("sodium".equals(qName)) {
            xmlReader.setContentHandler(new IgnoringContentHandler(xmlReader,
                    this));
        } else {
            System.out.println("START " + qName);
        }
    }
    public void endElement(String uri, String localName, String qName)
            throws SAXException {
        System.out.println("END " + qName);
    }
    public void characters(char[] ch, int start, int length)
            throws SAXException {
        System.out.println(new String(ch, start, length));
    }
}

忽略ContentHandler

当IgnoringContentHandler完成吞咽事件后，它将控制权传递回您的主ContentHandler。

import org.xml.sax.Attributes;
import org.xml.sax.ContentHandler;
import org.xml.sax.SAXException;
import org.xml.sax.XMLReader;
import org.xml.sax.helpers.DefaultHandler;
public class IgnoringContentHandler extends DefaultHandler {
    private int depth = 1;
    private XMLReader xmlReader;
    private ContentHandler contentHandler;
    public IgnoringContentHandler(XMLReader xmlReader, ContentHandler contentHandler) {
        this.contentHandler = contentHandler;
        this.xmlReader = xmlReader;
    }
    public void startElement(String uri, String localName, String qName,
            Attributes atts) throws SAXException {
        depth++;
    }
    public void endElement(String uri, String localName, String qName)
            throws SAXException {
        depth--;
        if(0 == depth) {
           xmlReader.setContentHandler(contentHandler);
        }
    }
}

以上是 用sax跳过节点 的全部内容， 来源链接： utcz.com/qa/398714.html

回到顶部