选择XML节点作为行
我从具有使用T-SQL的XML列的表中选择。我想选择某种类型的节点,并为每个节点创建一行。
例如,假设我要从 人员 表中进行选择。该表具有用于 地址 的XML列。XML的格式类似于以下格式:
<address> <street>Street 1</street>
<city>City 1</city>
<state>State 1</state>
<zipcode>Zip Code 1</zipcode>
</address>
<address>
<street>Street 2</street>
<city>City 2</city>
<state>State 2</state>
<zipcode>Zip Code 2</zipcode>
</address>
我如何获得这样的结果:
听听听听听听听听听 听听听听听听听听听
乔·贝克|西雅图WA
乔·贝克|塔科马| WA
弗雷德·琼斯温哥华
回答:
这是您的解决方案:
/* TEST TABLE */DECLARE @PEOPLE AS TABLE ([Name] VARCHAR(20), [Address] XML )
INSERT INTO @PEOPLE SELECT
'Joel',
'<address>
<street>Street 1</street>
<city>City 1</city>
<state>State 1</state>
<zipcode>Zip Code 1</zipcode>
</address>
<address>
<street>Street 2</street>
<city>City 2</city>
<state>State 2</state>
<zipcode>Zip Code 2</zipcode>
</address>'
UNION ALL SELECT
'Kim',
'<address>
<street>Street 3</street>
<city>City 3</city>
<state>State 3</state>
<zipcode>Zip Code 3</zipcode>
</address>'
SELECT * FROM @PEOPLE
-- BUILD XML
DECLARE @x XML
SELECT @x =
( SELECT
[Name]
, [Address].query('
for $a in //address
return <address
street="{$a/street}"
city="{$a/city}"
state="{$a/state}"
zipcode="{$a/zipcode}"
/>
')
FROM @PEOPLE AS people
FOR XML AUTO
)
-- RESULTS
SELECT [Name] = T.Item.value('../@Name', 'varchar(20)'),
street = T.Item.value('@street' , 'varchar(20)'),
city = T.Item.value('@city' , 'varchar(20)'),
state = T.Item.value('@state' , 'varchar(20)'),
zipcode = T.Item.value('@zipcode', 'varchar(20)')
FROM @x.nodes('//people/address') AS T(Item)
/* OUTPUT*/
Name | street | city | state | zipcode
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Joel | Street 1 | City 1 | State 1 | Zip Code 1
Joel | Street 2 | City 2 | State 2 | Zip Code 2
Kim | Street 3 | City 3 | State 3 | Zip Code 3
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