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我在Oracle数据库中的列具有这样的数据拆分列在甲骨文
column1 /opt/log/data/abcd.efghi.jklmn.aaa.txt
/opt/log/data/abbbcd.efccghi.jkdsdflmn.abab.txt
/opt/log/data/nmvcnmcd.efjhjghi.jkvslmn.abcbc.txt
/opt/log/data/hjsdhj.hjfdhdf.hdfhjd.aghag.txt
/opt/log/data/dfhjfdhj.yureyer.qwtyq.hjahjh.txt
我想在这样的方式
**firstdot seconddot thirdnfourthdot** abcd efghi jklmn.aaa
abbbcd efccghi jkdsdflmn.abab
nmvcnmcd efjhjghi jkvslmn.abcbc
hjsdhj hjfdhdf hdfhjd.aghag
dfhjfdhj yureyer qwtyq.hjahjh
我能得到的数据拆分第二点值由
select substr(column1,instr(column1,'.',1+1,instr(column1,'.',1,2)-instr(column1,'.',1,1)-1) as secondot
但我没有得到休息。你们能帮忙吗?
非常感谢
回答:
没有正则表达式,你需要回复同样的逻辑为你需要的每个子串,每个timi根据th的位置选择初始位置和leght该子字符串的e“终止符”。
/* input data */ with yourTable(column1) as (
select '/opt/log/data/abcd.efghi.jklmn.aaa.txt' from dual union all
select '/opt/log/data/abbbcd.efccghi.jkdsdflmn.abab.txt' from dual union all
select '/opt/log/data/nmvcnmcd.efjhjghi.jkvslmn.abcbc.txt' from dual union all
select '/opt/log/data/hjsdhj.hjfdhdf.hdfhjd.aghag.txt' from dual union all
select '/opt/log/data/dfhjfdhj.yureyer.qwtyq.hjahjh.txt' from dual
)
/* query */
select substr(column1, instr(column1, '/', -1) +1, instr(column1, '.') - instr(column1, '/', -1)-1) firstDot,
substr(column1, instr(column1, '.') +1, instr(column1, '.', 1, 2) - instr(column1, '.') -1) secondDot,
substr(column1, instr(column1, '.', 1, 2) +1, instr(column1, '.', 1, 4) - instr(column1, '.', 1, 2) -1) thirdAndFourthDot
from yourTable
给出:
FIRSTDOT SECONDDOT THIRDANDFOURTHD --------------- --------------- ---------------
abcd efghi jklmn.aaa
abbbcd efccghi jkdsdflmn.abab
nmvcnmcd efjhjghi jkvslmn.abcbc
hjsdhj hjfdhdf hdfhjd.aghag
dfhjfdhj yureyer qwtyq.hjahjh
在一个更可读的方式:
select substr(column1, lastSlashPos +1, firstDotPos - lastSlashPos -1) as firstDot, substr(column1, firstDotPos +1, secondDotPos - firstDotPos -1) as secondDot,
substr(column1, secondDotPos +1, fourthDotPos - secondDotPos -1) as thirdAndFourthDot
from (
select instr(column1, '/', -1) as lastSlashPos,
instr(column1, '.') as firstDotPos,
instr(column1, '.', 1, 2) as secondDotPos,
instr(column1, '.', 1, 3) as thirdDotPos,
instr(column1, '.', 1, 4) as fourthDotPos,
column1
from yourTable
)
回答:
select substr('/opt/log/data/abcd.efghi.jklmn.aaa.txt',instr('/opt/log/data/abcd.efghi.jklmn.aaa.txt','/',-1) + 1) from dual;
这会给你以后最后/
文本,然后你需要申请instr
为.
:
select substr(text, 1, instr(text,'.', 1) - 1),
substr(text, instr(text,'.', 1) + 1, instr(text,'.', 2) - 1),
substr(text, instr(text,'.', 2) + 1)
from (
select substr('/opt/log/data/abcd.efghi.jklmn.aaa.txt',instr('/opt/log/data/abcd.efghi.jklmn.aaa.txt','/',-1) + 1) text from dual
);
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