从其他阵列过滤对象

• Z时代
• 2024-01-10
• 分类：问答

我想实现的是，如果fleetArray中的任何fleet_id存在于om对象中，那么我想从om对象中删除它。 有没有更好的方法来做到这一点？从其他阵列过滤对象

var newObject= {} 
newObject.data=[] 
var om = { 
    "message": "Successful", 
    "status": 200, 
    "data": [{ 
     "tag": "", 
     "array": [ 
      { 
      "type": 0, 
      "fleet_id": 23508, 
     }, 
     { 
      "type": 10, 
      "fleet_id": 235089, 
     } 
     ] 
    }, { 
     "tag": "", 
     "array": [{ 
      "type": 320, 
      "fleet_id": 23218, 
     }] 
    }] 
} 
var fleetArray = ["23218","23508"]; 
om.data.forEach(function(api){ 
    //console.log(api) 
    (api.array).forEach(function(data1){ 
    fleetArray.forEach(function(fleet){ 
     if(fleet==data1.fleet_id){ 
     newObject.data.push(data1) 
     } 
    }) 
    }) 
}) 
console.log(newObject) 

回答：

om.data = om.data.map(e => { 
    e.array = e.array.filter(a => ! fleetArray.includes("" + a.fleet_id)) 
    return e; 
}); 

var om = {"message": "Successful","status": 200,"data": [{"tag": "","array": [{"type": 0,"fleet_id": 23508,},{"type": 10,"fleet_id": 235089,}]}, {"tag": "","array": [{"type": 320,"fleet_id": 23218,}]}]}  
var fleetArray = ["23218","23508"];  
om.data = om.data.map(e => {  
    e.array = e.array.filter(a => ! fleetArray.includes("" + a.fleet_id))  
    return e;  
});  
console.log(om);

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