从json解析中插入数据到sqlite数据库
我想在android数据解析表单中的json数组数据中插入数据到sqLite数据库。从json解析中插入数据到sqlite数据库" title="sqlite数据库">sqlite数据库
我的代码如下:
1)DBHelperClass - 数据库创建
public class DueAmountDataBHelper extends SQLiteOpenHelper { public DueAmountDataBHelper(Context context) {
super(context, "abc.db", null, 1);
}
@Override
public void onCreate(SQLiteDatabase db) {
String CREATE_TABLE_PRODUCT_DUE_AMT =
"create table due_amt_tab(" +
"shopId text primary key, " +
"shopName text NOT NULL, " +
"teluguName text NOT NULL, " +
"place text NOT NULL, " +
"dueAmount text NOT NULL " +
")";
db.execSQL(CREATE_TABLE_PRODUCT_DUE_AMT);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
}
public List<DueAmtDBModel> getShopdata() {
List<DueAmtDBModel> data = new ArrayList<>();
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery("select * from due_amt_tab", null);
StringBuffer stringBuffer = new StringBuffer();
DueAmtDBModel dataModel = null;
while (cursor.moveToNext()) {
dataModel = new DueAmtDBModel();
String shopId, shopName, teluguName, place, dueAmount;
shopId = cursor.getString(cursor.getColumnIndexOrThrow("shopId"));
shopName = cursor.getString(cursor.getColumnIndexOrThrow("shopName"));
teluguName = cursor.getString(cursor.getColumnIndexOrThrow("teluguName"));
place = cursor.getString(cursor.getColumnIndexOrThrow("place"));
dueAmount = cursor.getString(cursor.getColumnIndexOrThrow("dueAmount"));
dataModel.setShopId(shopId);
dataModel.setShopName(shopName);
dataModel.setTeluguName(teluguName);
dataModel.setPlace(place);
dataModel.setDueAmount(dueAmount);
stringBuffer.append(dataModel);
data.add(dataModel);
}
return data;
}
}
这个表我需要插入此JSON数据
APi的 - http://demo4896782.mockable.io/shops
[ {
"shopName": "Hello World.",
"shopTeluguName": "శరవాన గుడ్డు పంపిణీదారులు",
"shopAddress": "Bomanahalli",
"previousDues": 0,
"shopID": 1
},
{
"shopName": "Hello World.",
"shopTeluguName": "శరవాన గుడ్డు పంపిణీదారులు",
"shopAddress": "Bomanahalli",
"previousDues": 20,
"shopID": 2
},
{
"shopName": "Hello World.",
"shopTeluguName": "శరవాన గుడ్డు పంపిణీదారులు",
"shopAddress": "Bomanahalli",
"previousDues": 400,
"shopID": 3
}
]
预先感谢您。
回答:
下面的代码假设您可以解析服务器的json数据。
public void insert(JsonObject jsonObject){ ContentValues values = new ContentValues();
SQLiteDatabase db = this.getWritableDatabase();
values.put("shopName", jsonObject.getString('Hello World'));
values.put("shopTeluguName", jsonObject.getString('shopTeluguName'));
values.put("shopAddress", jsonObject.getString('shopAddress'));
values.put("previousDues", jsonObject.getString('previousDues'));
values.put("shopID", jsonObject.getString('shopID'));
db.insert("YOUR TABLE NAME", null, values);
}
现在只需遍历JSON阵列,并呼吁在循环
回答:
首先这个功能,表结构应该是:
CREATE TABLE IF NOT EXISTS "TABLE_NAME" + "(" + JSON_STRING_KEY + " TEXT ")
现在,做一个模型类对于你从api获得的json数组。现在
,以插入此JSON-数组中的表,你可以做这样的事情:
void insertJsonArrayAsStringToTable(ArrayList<Model> modelList) { SQLiteDatabase db = this.getWritableDatabase();
db.delete(TABLE_NAME, null, null); // delete previous data
ContentValues contentValues = new ContentValues();
// array list as a string; or you can directly put the string you got from
// onResponse(String response) of your volley StringRequest--if you're using it
contentValues.put(JSON_STRING_KEY, new Gson().toJsonTree(modelList).toString());
db.insert(TABLE_NAME, null, contentValues);
db.close();
}
到现在为止,我们已经从存储在表中作为API的JSON数组数据一个字符串。
现在,我们可以使用查询从表检索字符串并再次使用GSON到它转换成一个对象(这里的Model
的ArrayList
):
public ArrayList<Model> loadData() { SQLiteDatabase db = this.getReadableDatabase();
Cursor res = db.rawQuery("SELECT * FROM " + TABLE_NAME, null); // now where-clause, so we simply use null as an arguement
res.moveToFirst();
ArrayList<Model> modelList= null;
while (!res.isAfterLast()) { // traverse the table
Type listType = new TypeToken<ArrayList<Model>>() {
}.getType();
modelList= new Gson().fromJson(res.getString(res.getColumnIndex(JSON_STRING_KEY)), listType);
res.moveToNext();
}
res.close();
db.close();
return modelList;
}
PS:如何你设法将来自API的其他可能的响应存储到数据库中,完全取决于你,无论是制作单独的表还是类似的东西。
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