提取卷曲API在Android中Java的

  • Z时代
  • 2024-01-10
  • 分类：问答

我尝试使用以下cURL命令提取从EatStreet API数据：提取卷曲API在Android中Java的

卷曲-X GET \ -H 'X-访问令牌：API_EXPLORER_AUTH_KEY' \ “https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.4310&longitude=-86.9149&method=both”

我写了到目前为止的代码如下：

import org.apache.http.auth.UsernamePasswordCredentials; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.methods.HttpGet; 
import org.apache.http.impl.auth.BasicScheme; 
import org.apache.http.impl.client.DefaultHttpClient; 
import java.io.BufferedReader; 
import java.lang.StringBuffer; 
import java.net.URI; 
import java.net.URISyntaxException; 
public class Main { 
    public static void main(String[] args) { 
     StringBuffer stringBuffer = new StringBuffer(""); 
     BufferedReader bufferedReader = null; 
     blah(); 
    } 
    private static void blah() { 
     try { 
      HttpClient httpClient = new DefaultHttpClient(); 
      HttpGet httpGet = new HttpGet(); 
      URI uri = new URI("https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.4310&longitude=-86.9149&method=both"); 
      httpGet.setURI(uri); 
      addHeader(httpGet); 
     } 
     catch (URISyntaxException e) { 
      e.printStackTrace(); 
     } 
     catch (Exception e) { 
      e.printStackTrace(); 
     } 
    } 
    private void addHeader(HttpGet httpGet) { 
     httpGet.addHeader(BasicScheme.authenticate(new UsernamePasswordCredentials("X-Access-Token", 
         "__API_EXPLORER_AUTH_KEY__"), null)); 
    } 
}

此代码是不是在所有我相信任何输出是由于WR ong身份验证。我需要使用Android上面提到的cURL命令来获取数据。

输出应该类似于如下（JSON格式）：

{ 
    "address": { 
    "apiKey": null, 
    "streetAddress": null, 
    "latitude": 40.431, 
    "longitude": -86.9149, 
    "city": null, 
    "state": null, 
    "zip": null, 
    "aptNumber": null 
    }, 
    "restaurants": [ 
    { 
     "apiKey": "90fd4587554469b1144247b91fbcb2f349e8e58504b5a530", 
     "deliveryMin": 7, 
     "deliveryPrice": 3, 
     "logoUrl": "/wp-content/uploads/new2022/20220327voicc/151153129.png", 
     "name": "Egyptian Cafe and Hooka Bar", 
     "streetAddress": "130 Northwestern Avenue", 
     "city": "West Lafayette", 
     "state": "IN", 
     "zip": "47906", 
     "foodTypes": [ 
     "Subs & Sandwiches", 
     "Middle Eastern Food", 
     "Mediterranean Food", 
     "Hookah Bars", 
     "Healthy Food" 
     ], 
     . 
     . 
     . 
     { 
     "apiKey": "90fd4587554469b1144247b91fbcb2f3720a4edae037dd96", 
     "deliveryMin": 7, 
     "deliveryPrice": 3, 
     "logoUrl": "/wp-content/uploads/new2022/20220327voicc/152153129.png", 
     "name": "Vienna Coffee House & Bakery", 
     "streetAddress": "208 South Street", 
     "city": "West Lafayette", 
     "state": "IN", 
     "zip": "47906", 
     "foodTypes": [ 
     "Coffee & Tea", 
     "Bakery" 
     ], 
     "phone": "(765) 743-4446", 
     "latitude": 40.4239543, 
     "longitude": -86.9079021, 
     "minFreeDelivery": 0, 
     "taxRate": 0.07, 
     "acceptsCash": false, 
     "acceptsCard": true, 
     "offersPickup": true, 
     "offersDelivery": true, 
     "isTestRestaurant": false, 
     "minWaitTime": 45, 
     "maxWaitTime": 60, 
     "open": true, 
     "url": "https://eatstreet.com/lafayette-in/restaurants/vienna-coffee-house-and-bakery", 
     "hours": { 
     "Sunday": [ 
      "6:00 PM - 12:00 AM" 
     ], 
     "Wednesday": [ 
      "6:00 PM - 12:00 AM" 
     ], 
     "Tuesday": [ 
      "6:00 PM - 12:00 AM" 
     ] 
     }, 
     "timezone": "US/Eastern" 
    } 
    ] 
}

回答：

您addHeader(httpGet)后，你必须用实际执行的GET操作先前定义的httpClient：

HttpResponse response = httpclient.execute(httpGet); 
response.getEntity().getContent(); // do something with the response 
// an example of continuing what you were trying to do 
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(
     response.getEntity().getContent()));

而且，您的addHeader(httpGet)需要更改为此，以传递API密钥作为标题，而不是UsernamePasswordCredentials

private static void addHeader(HttpGet httpGet) { 
     httpGet.addHeader("X-Access-Token", "__API_EXPLORER_AUTH_KEY__"); 
}

以上是 提取卷曲API在Android中Java的 的全部内容， 来源链接： utcz.com/qa/259822.html

回到顶部