如何摆脱随机函数的动态链接？

Z时代
2024-01-10
分类：问答

我要拿出刚才的动态链接，但这里并不是所有的对象：如何摆脱随机函数的动态链接？

function random_imglink(){ 
     var myimages=new Array() 
     //specify random images below. You can have as many as you wish 
     myimages[1]="/documents/templates/bilgiteknolojileri/standalone.swf" 
     myimages[2]="/documents/templates/bilgiteknolojileri/mobil.swf" 
     myimages[3]="/documents/templates/bilgiteknolojileri/3b2.swf" 
     var ry=Math.floor(Math.random()*myimages.length) 
     if (ry==0) 
     ry=1 
     document.write('<embed wmode="transparent" src="'+myimages[ry]+'" height="253" width="440"></embed>') 
    } 
    random_imglink()

我的意思是，让水木清华像$ random_link $动态链接，这样我可以把它放在HTML代码

<embed wmode="transparent" src="$random_link$" height="253" width="440"></embed>

回答：

function randomItem(theArray) { 
    return theArray[Math.floor(theArray.length * Math.random())]; 
} 
myImages = ["some","image","paths"]; 
var theFlashElement = '<embed wmode="transparent" src="' + randomItem(myImages) + '" height="253" width="440"></embed>'; 
document.getElementById("flashContainerId").innerHTML = theFlashElement;

回答：

我很难搞清楚你问的是什么，但是如果你想从函数中获得链接（也许作为返回值），以便脱离document.write（几乎总是一个好主意摆脱），那么：

function random_imglink(){ 
    var myimages=new Array() 
    //specify random images below. You can have as many as you wish 
    myimages[1]="/documents/templates/bilgiteknolojileri/standalone.swf" 
    myimages[2]="/documents/templates/bilgiteknolojileri/mobil.swf" 
    myimages[3]="/documents/templates/bilgiteknolojileri/3b2.swf" 
    var ry=Math.floor(Math.random()*myimages.length) 
    if (ry==0) { 
    ry=1; 
    } 
    return myimages[ry]; 
} 
alert(random_imglink()); // alerts one of the three paths above

题外话：下面是函数清理了一些：

function random_imglink(){ 
    //specify random images below. You can have as many as you wish 
    var myimages = [ 
     "/documents/templates/bilgiteknolojileri/standalone.swf", 
     "/documents/templates/bilgiteknolojileri/mobil.swf", 
     "/documents/templates/bilgiteknolojileri/3b2.swf" 
    ]; 
    return myimages[Math.floor(Math.random()*myimages.length)]; 
} 
alert(random_imglink()); // alerts one of the three paths above

变化：