测试如果一个变量有数字或字母或两者/无LUA

• Z时代
• 2024-01-10
• 分类：问答

进出口试图找出如何在Lua检查一个字符串变量中有任何字母或数字，像这样：测试如果一个变量有数字或字母或两者/无LUA

myAwesomeVar = "hi there crazicrafter1" 
if myAwesomeVar(has letters and numbers) then 
    print("It has letters and numbers!") 
elseif myAwesomeVar(has letters and not numbers) then 
    print("It has letters!, but no numbers...") 
elseif myAwesomeVar(has not letters and not numbers) then 
    print("It doesnt have letters or numbers...") 
elseif myAwesomeVar(has not letters and numbers) then 
    print("It doesnt have letters, but it has numbers!") 
end 

我知道这是不正确的一些论点，但这是我的目标是我的代码输出：

它有字母和数字！

回答：

function containsDigit(str) 
    return string.find(str, "%d") and true or false 
end 

local myString = "hello123" 
if containsDigit(myString) and containsDigit(myString) then 
    print("contains both") 
end 

以上是 测试如果一个变量有数字或字母或两者/无LUA 的全部内容， 来源链接： utcz.com/qa/258774.html