如何在pygame中实现两个输入框，而不必重复代码

您可以创建方法类，它在吸引它并处理事件。然后你可以用很多次

全部工作示例

import pygame 
class InputBox(): 
    def __init__(self, x, y): 
     self.font = pygame.font.Font(None, 32) 
     self.inputBox = pygame.Rect(x, y, 140, 32) 
     self.colourInactive = pygame.Color('lightskyblue3') 
     self.colourActive = pygame.Color('dodgerblue2') 
     self.colour = self.colourInactive 
     self.text = '' 
     self.active = False 
     self.isBlue = True 
    def handle_event(self, event): 
     if event.type == pygame.MOUSEBUTTONDOWN: 
      self.active = self.inputBox.collidepoint(event.pos) 
      self.colour = self.colourActive if self.active else self.colourInactive 
     if event.type == pygame.KEYDOWN: 
      if self.active: 
       if event.key == pygame.K_RETURN: 
        print(self.text) 
        self.text = '' 
       elif event.key == pygame.K_BACKSPACE: 
        self.text = self.text[:-1] 
       else: 
        self.text += event.unicode 
    def draw(self, screen): 
     txtSurface = self.font.render(self.text, True, self.colour) 
     width = max(200, txtSurface.get_width()+10) 
     self.inputBox.w = width 
     screen.blit(txtSurface, (self.inputBox.x+5, self.inputBox.y+5)) 
     pygame.draw.rect(screen, self.colour, self.inputBox, 2) 
     if self.isBlue: 
      self.color = (0, 128, 255) 
     else: 
      self.color = (255, 100, 0) 
# --- main --- 
def mainloop(): 
    # create objects  
    input1 = InputBox(50, 50) 
    input2 = InputBox(450, 50) 
    clock = pygame.time.Clock() 
    while True: 
     for event in pygame.event.get(): 
      if event.type == pygame.QUIT: 
       pygame.quit() 
       sys.exit() 
      # handle every event 
      input1.handle_event(event) 
      input2.handle_event(event) 
     screen.fill((128,128, 128)) 
     # draw it 
     input1.draw(screen) 
     input2.draw(screen) 
     pygame.display.flip() 
     clock.tick(60) 
pygame.init()   
screen = pygame.display.set_mode((800,600)) 
mainloop() 

BTW：更多的投入，你可以让他们在列表（如在GUI框架）

def mainloop(): 
    widgets = [ 
     InputBox(50, 50), 
     InputBox(450, 50), 
     InputBox(50, 150), 
     InputBox(450, 150), 
     InputBox(50, 250), 
     InputBox(450, 250), 
     InputBox(50, 350), 
     InputBox(450, 350), 
    ] 
    clock = pygame.time.Clock() 
    while True: 
     for event in pygame.event.get(): 
      if event.type == pygame.QUIT: 
       pygame.quit() 
       sys.exit() 
      for child in widgets: 
       child.handle_event(event) 
     screen.fill((128,128, 128)) 
     for child in widgets: 
      child.draw(screen) 
     pygame.display.flip() 
     clock.tick(60) 

你可以创建一个类，并在需要不同的输入框进行实例化多次。

是这样的：

# pseudocode # 
class InputBox(pygame.Rect): 
    def __init__(self, position=(50, 50, 140, 32), 
       font=pygame.font.Font(None, 32), 
       color_inactive=pygame.Color('lightskyblue3'), 
       color_active=pygame.Color('dodgerblue2'), 
       text = '', 
       active=False) 
     super().__init__(position) #<- this may need to be adjusted to pygame Rect specs 
     self.font = font 
     self.color_inactive = color_inactive 
     self.color_active = color_active 
     self.color = color_inactive 
     self.text = text 
     self.active = active