Python 简单的多进程 报错，求助各位大佬？

  • Z时代
  • 2024-02-23
  • 分类：IT

Python 简单的多进程 报错，求助各位大佬？

import multiprocessing as mp
def test(que,a,b):
    r=a+b
    que.put(r)
if __name__ == '__main__':
    f = 1
    g = 1
    t = mp.Queue()
    k = mp.Process(target=test,args=(t,f,g))
    k.start()
    k.join()
    u = t.get()
Traceback (most recent call last):
  File "<string>", line 1, in <module>
  File "C:\Users\admin\AppData\Local\Programs\Python\Python39\lib\multiprocessing\spawn.py", line 116, in spawn_main
    exitcode = _main(fd, parent_sentinel)
  File "C:\Users\admin\AppData\Local\Programs\Python\Python39\lib\multiprocessing\spawn.py", line 125, in _main
    prepare(preparation_data)
  File "C:\Users\admin\AppData\Local\Programs\Python\Python39\lib\multiprocessing\spawn.py", line 236, in prepare
    _fixup_main_from_path(data['init_main_from_path'])
  File "C:\Users\admin\AppData\Local\Programs\Python\Python39\lib\multiprocessing\spawn.py", line 287, in _fixup_main_from_path
    main_content = runpy.run_path(main_path,
  File "C:\Users\admin\AppData\Local\Programs\Python\Python39\lib\runpy.py", line 267, in run_path
    code, fname = _get_code_from_file(run_name, path_name)
  File "C:\Users\admin\AppData\Local\Programs\Python\Python39\lib\runpy.py", line 237, in _get_code_from_file
    with io.open_code(decoded_path) as f:
OSError: [Errno 22] Invalid argument: 'C:\\Users\\admin\\Desktop\\销售绩效等级\\<input>'

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