c++ 解决无法打印uint8_t 类型变量的问题

将uint8_t 转化为unsigned 类型

使用一元运算符+(和- 运算符对应)

测试代码如下

#include <cstdint>

#include <iostream>

#include <typeinfo>

int main()

{

std::uint8_t uint8_num = 10;

std::cout << "uint8_t num is " << uint8_num << std::endl; //无法打印

std::cout << "after cast to unsigned, uint8_t num is " << unsigned(uint8_num) << std::endl; //能正常打印

std::cout << "with a unary + operator, uint8_t num is " << +uint8_num << std::endl; //能正常打印

std::cout << "type of '+uint8_num' is " << typeid(+uint8_num).name() << std::endl;

return 0;

}

运行结果如下

可见使用+运算符的原理也是进行类型转换(把uint8_t 转为 int)

补充知识:C 语言printf打印各种数据类型的方法(u8/s8/u16/s16.../u64/double/float)(全)

首先必须知道u8,s8等数据类型的定义:

typedef signed char s8;

typedef unsigned char u8;

typedef signed short s16;

typedef unsigned short u16;

typedef signed int s32;

typedef unsigned int u32;

typedef signed long long s64;

typedef unsigned long long u64;

与体系结构相关的,定义在include/linux/type.h文件中:

/* bsd */

typedef unsigned char u_char;

typedef unsigned short u_short;

typedef unsigned int u_int;

typedef unsigned long u_long;

/* sysv */

typedef unsigned char unchar;

typedef unsigned short ushort;

typedef unsigned int uint;

typedef unsigned long ulong;

#ifndef __BIT_TYPES_DEFINED__

#define __BIT_TYPES_DEFINED__

typedef __u8 u_int8_t;

typedef __s8 int8_t;

typedef __u16 u_int16_t;

typedef __s16 int16_t;

typedef __u32 u_int32_t;

typedef __s32 int32_t;

#endif /* !(__BIT_TYPES_DEFINED__) */

typedef __u8 uint8_t;

typedef __u16 uint16_t;

typedef __u32 uint32_t;

#if defined(__GNUC__)

typedef __u64 uint64_t;

typedef __u64 u_int64_t;

typedef __s64 int64_t;

对于各种数据类型的打印方式总结如下如下:

数据类型打印格式
u8%d
s8%d
u16%d or %hu
s16%d or %hd
u32%u
s32%d
u64%llu
s64%lld
int%d
unsigned int%u
short int%d or %hd
long%ld
unsigned long%lu
long long%lld
unsigned long long%llu
char%c
char *%s
bool (#define stdbool.h)%d
unsigned int/int------>十六进制%0x
unsigned long/long---->十六进制%0lx
long long/unsigned long long ----->十六进制%0llx
unsigned int/int------>八进制%0o
unsigned long/long---->八进制%0lo
long long/unsigned long long ----->八进制%0llo
float%f
double%f or %lf
科学技术类型(必须转化为double类型)%e
限制输出字段宽度%x.yf (x:整数长度,y:小数点长度)

待解问题,在linux kernel里面也有使用bool来定义变量,查看code,定义如下:

typedef _Bool bool;

但是并没有真正找到具体定义在何处,待解。

下面是stdbool.h的source code:

#define _STDBOOL_H

#ifndef __cplusplus

#define bool _Bool

#define true 1

#define false 0

#else /* __cplusplus */

/* Supporting _Bool in C++ is a GCC extension. */

#define _Bool bool

#if __cplusplus < 201103L

/* Defining these macros in C++98 is a GCC extension. */

#define bool bool

#define false false

#define true true

#endif

#endif /* __cplusplus */

/* Signal that all the definitions are present. */

#define __bool_true_false_are_defined 1

#endif /* stdbool.h */

也大致解释了linux kernel bool type了。

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