功能型消息推送功能如何实现(带同意 拒绝)

  • Z时代
  • 2024-01-10
  • 分类：IT

图片描述

比如如上图的那种推送功能
现在哪些推送平台可以实现这种功能

回答：

@erehmi 说的不错，根据厂商会有所不同。

给你举个原生android例子：

<?xml version="1.0" encoding="UTF-8"?>  
 <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"  
   android:layout_width="fill_parent"  
   android:layout_height="fill_parent"  
   android:gravity="center"  
   android:orientation="horizontal" >  
   <TextView  
     android:id="@+id/textView1"  
     android:layout_width="wrap_content"  
     android:layout_height="wrap_content"  
     android:gravity="center"  
     android:text="DJ notification"  
     android:textAppearance="?android:attr/textAppearanceMedium" />  
   <Button  
     android:id="@+id/button1"  
     android:layout_width="wrap_content"  
     android:layout_height="wrap_content"  
     android:text="Close Me" />  
 </LinearLayout> 

RemoteViews remoteViews = new RemoteViews(getPackageName(),  
                     R.layout.widget);  
           NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(  
                     this).setSmallIcon(R.drawable.ic_launcher).setContent(  
                     remoteViews);  
           // Creates an explicit intent for an Activity in your app  
           Intent resultIntent = new Intent(this, test.class);  
           // The stack builder object will contain an artificial back stack for  
           // the  
           // started Activity.  
           // This ensures that navigating backward from the Activity leads out of  
           // your application to the Home screen.  
           TaskStackBuilder stackBuilder = TaskStackBuilder.create(this);  
           // Adds the back stack for the Intent (but not the Intent itself)  
           stackBuilder.addParentStack(test.class);  
           // Adds the Intent that starts the Activity to the top of the stack  
           stackBuilder.addNextIntent(resultIntent);  
           PendingIntent resultPendingIntent = stackBuilder.getPendingIntent(0,  
                     PendingIntent.FLAG_UPDATE_CURRENT);  
           remoteViews.setOnClickPendingIntent(R.id.button1, resultPendingIntent);  
           NotificationManager mNotificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);  
           // mId allows you to update the notification later on.  
           mNotificationManager.notify(100, mBuilder.build());

回答：

推送一般分为两种:

  1. 推送通知

  2. 透传消息

推送通知一般是推送提供商帮你已经实现基本界面交互(包括收到通知后状态栏通知消息提醒, 通知点击行为), 这类是比较常用的. 而透传消息它只负责接收, 而不管前端展示, 这种消息正好能解决题主的需求: 客户端收到透传消息后, 自己编写代码弹出自定义样式的状态栏通知.

请参考各大推送厂商的SDK文档.

回答：

iOS在8.0之后就可以自定义推送信息显示按钮, 并且通过代理监听用户对推送消息操作.

1.在UIApplication中有对推送消息进行设置的方法

- (void)registerUserNotificationSettings:(UIUserNotificationSettings *)notificationSettings

图片描述
2.UIUserNotificationSettings类中可以对消息添加用户行为(如: 按钮)

+ (instancetype)settingsForTypes:(UIUserNotificationType)types
                      categories:(nullable NSSet<UIUserNotificationCategory *> *)categories;

图片描述

3.添加UIUserNotificationAction,用于用户操作.

- (void)setActions:(nullable NSArray<UIUserNotificationAction *> *)actions forContext:(UIUserNotificationActionContext)context;

图片描述

推送截图:

代码:(参考链接)

[[UIApplication sharedApplication] registerForRemoteNotifications];
UIMutableUserNotificationAction *actionAccept = [[UIMutableUserNotificationAction alloc] init];
actionAccept.identifier = @"accept";
actionAccept.title=@"√ 允许";
actionAccept.activationMode = UIUserNotificationActivationModeForeground;
actionAccept.destructive = YES;
UIMutableUserNotificationAction * actionReject = [[UIMutableUserNotificationAction alloc] init];
actionReject.identifier = @"reject";
actionReject.title=@"× 拒绝";
actionReject.activationMode = UIUserNotificationActivationModeBackground;
actionReject.authenticationRequired = NO;
actionReject.destructive = NO;
UIMutableUserNotificationCategory *category = [[UIMutableUserNotificationCategory alloc] init];
category.identifier = @"Category";
[category setActions:@[actionReject,actionAccept] forContext:(UIUserNotificationActionContextDefault)];
UIUserNotificationSettings *uns = [UIUserNotificationSettings settingsForTypes:(UIUserNotificationTypeAlert|UIUserNotificationTypeBadge|UIUserNotificationTypeSound) categories:[NSSet setWithObjects: category, nil]];
[[UIApplication sharedApplication] registerUserNotificationSettings: uns];

回答：

使用自定义消息都可以做到。

题主说的这个是通知的样式，和推送关系不大。虽然推送通常也会带一个简单样式的默认通知，但是一般还是会使用自定义消息然后自己去定制通知的样式。

以上是 功能型消息推送功能如何实现(带同意 拒绝) 的全部内容， 来源链接： utcz.com/p/187803.html

回到顶部