retrofit2.0 post提交一直返回400,用httpurlconnection就可以

1.用retrofit2.0 post提交 json
@POST("AppLoginIn")

Call<JsonObject> getLoginUser(@Body String parameterJson);

//待提交的json数据
private String toJsonUser() {

    JSONStringer jsonStringer = null;

try {

jsonStringer = new JSONStringer().object().key("LoginCode").value("SUPERMAN").key("Password")

.value("111111").endObject();

} catch (JSONException e) {

e.printStackTrace();

}

Log.i("", "---json user:" + jsonStringer.toString());

return jsonStringer.toString();

}

//retrofit 请求

private void postYDL(String jsonString) {

Retrofit retrofit = new Retrofit.Builder().baseUrl(url)

.addConverterFactory(GsonConverterFactory.create())

.build();

IService iService = retrofit.create(IService.class);

Call<JsonObject> call = iService.getLoginUser(jsonString);

call.enqueue(new Callback<JsonObject>() {

@Override

public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {

String responseData = "---body:" + response.body()

    • "n---message:" + response.message()

    • "n---headers:" + response.headers()

    • "n---code:" + response.code()

    • "n---isSuccessful:" + response.isSuccessful();

                 Log.i("", "---base action responseData:" + responseData);

      tv1.setText(responseData);

      }

      @Override

    1. void onFailure(Call<JsonObject> call, Throwable t) {

                 tv1.setText(t.getMessage());

      }

      });

      }
      图片描述

      换另一个请求地址结果:

    图片描述

    以上是 retrofit2.0 post提交一直返回400,用httpurlconnection就可以 的全部内容, 来源链接: utcz.com/p/177916.html

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