retrofit2.0 post提交一直返回400,用httpurlconnection就可以
1.用retrofit2.0 post提交 json
@POST("AppLoginIn")
Call<JsonObject> getLoginUser(@Body String parameterJson);
//待提交的json数据
private String toJsonUser() {
JSONStringer jsonStringer = null; try {
jsonStringer = new JSONStringer().object().key("LoginCode").value("SUPERMAN").key("Password")
.value("111111").endObject();
} catch (JSONException e) {
e.printStackTrace();
}
Log.i("", "---json user:" + jsonStringer.toString());
return jsonStringer.toString();
}
//retrofit 请求
private void postYDL(String jsonString) {
Retrofit retrofit = new Retrofit.Builder().baseUrl(url)
.addConverterFactory(GsonConverterFactory.create())
.build();
IService iService = retrofit.create(IService.class);
Call<JsonObject> call = iService.getLoginUser(jsonString);
call.enqueue(new Callback<JsonObject>() {
@Override
public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
String responseData = "---body:" + response.body()
"n---message:" + response.message()
"n---headers:" + response.headers()
"n---code:" + response.code()
"n---isSuccessful:" + response.isSuccessful();
Log.i("", "---base action responseData:" + responseData);
tv1.setText(responseData);
}
@Override
void onFailure(Call<JsonObject> call, Throwable t) {
tv1.setText(t.getMessage());
}
});
}
换另一个请求地址结果:
以上是 retrofit2.0 post提交一直返回400,用httpurlconnection就可以 的全部内容, 来源链接: utcz.com/p/177916.html