如何统计 文本 中的 空格数 和 数字 的个数 ?
Python新手求教,还望详解!
想要实现实现的功能:
统计一个文本中的空格数和数字的个数。
具体如下:
文本:
4 8 15 16 23 42 520 I LOVE LOST.
得出结果:
number_counts = 7space_counts = 13 #42和520之间有5个空格,4~42之间都是一个1个空格
更新部分:
根据 @banagoo 提高的答案,我的代码:(还是有问题?)
import osos.chdir('/Users/apple/Desktop/Python/chapter')
file_name = "lost.txt"
space_counts = 0
number_counts = 0
with open(file_name, 'r') as f:
for line in f:
space_counts += len( line.split() )
number_list = [x for x in line.split() if x.isdigit()]
number_counts = len(number_list)
print "space_counts", space_counts
print "number_counts",number_counts
文本:
4 8 15 16 23 42 520 I LOVE LOST.4 8 15 16 23 42 520 I LOVE YOU.
发现答案不对呀!求指教?
谢谢 @banagoo 的帮助,可运行的代码如下:
import osos.chdir('/Users/apple/Desktop/Python/chapter')
file_name = "lost.txt"
space_counts = 0
number_counts = 0
number_list = []
with open(file_name, 'r') as f:
for line in f:
line = line.strip()
space_split_list = line.split(' ')
space_counts += len(space_split_list) - 1
for word in space_split_list:
if word.isdigit():
number_list.append(word)
number_counts = len(number_list)
print "space_counts", space_counts
print "number_counts", number_counts
回答:
input_str = '4 8 15 16 23 42 520 I LOVE LOST.'space_split_list = input_str.split(' ')
space_counts = len(space_split_list) - 1
number_list = [x for x in space_split_list if x.isdigit()]
number_counts = len(number_list)
import osos.chdir('/Users/apple/Desktop/Python/chapter')
file_name = "lost.txt"
space_counts = 0
number_counts = 0
with open(file_name, 'r') as f:
for line in f:
line = line.strip() # 每行行首,行尾的空格会被忽略
space_split_list = line.split(' ')
space_counts += len(space_split_list) - 1
number_list = [x for x in space_split_list if x.isdigit()]
number_counts = len(number_list)
print "space_counts", space_counts
print "number_counts", number_counts
回答:
可以尝试用正则表达式。
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