mysql互换表中两列数据方法

database

1.创建表及记录用于测试

CREATE TABLE product (

id int(10) unsigned NOT NULL AUTO_INCREMENT COMMENT "产品id",

name varchar(50) NOT NULL COMMENT "产品名称",

original_price decimal(5,2) unsigned NOT NULL COMMENT "原价",

price decimal(5,2) unsigned NOT NULL COMMENT "现价",

PRIMARY KEY (id)

) ENGINE=InnoDB DEFAULT CHARSET=utf8;

INSERT INTO product (id, name, original_price, price) VALUES

(NULL, "雪糕", "5", "3.5"),

(NULL, "鲜花", "18", "15"),

(NULL, "甜点", "25", "12.5"),

(NULL, "玩具", "55", "45"),

(NULL, "钱包", "285", "195");

mysql> select * from product;

+----+--------+----------------+--------+

| id | name | original_price | price |

+----+--------+----------------+--------+

| 1 | 雪糕 | 5.00 | 3.50 |

| 2 | 鲜花 | 18.00 | 15.00 |

| 3 | 甜点 | 25.00 | 12.50 |

| 4 | 玩具 | 55.00 | 45.00 |

| 5 | 钱包 | 285.00 | 195.00 |

+----+--------+----------------+--------+

5 rows in set (0.00 sec)

2.互换original_price与price的值

新手可能会使用以下方法进行互换

update product set original_price=price,price=original_price;

但这样执行的结果只会使original_price与price的值都是price的值,因为update有顺序的,

先执行original_price=price , original_price的值已经更新为price,

然后执行price=original_price,这里相当于没有更新。

执行结果

mysql> select * from product;

+----+--------+----------------+--------+

| id | name | original_price | price |

+----+--------+----------------+--------+

| 1 | 雪糕 | 5.00 | 3.50 |

| 2 | 鲜花 | 18.00 | 15.00 |

| 3 | 甜点 | 25.00 | 12.50 |

| 4 | 玩具 | 55.00 | 45.00 |

| 5 | 钱包 | 285.00 | 195.00 |

+----+--------+----------------+--------+

5 rows in set (0.00 sec)

mysql> update product set original_price=price,price=original_price;

Query OK, 5 rows affected (0.00 sec)

Rows matched: 5 Changed: 5 Warnings: 0

mysql> select * from product;

+----+--------+----------------+--------+

| id | name | original_price | price |

+----+--------+----------------+--------+

| 1 | 雪糕 | 3.50 | 3.50 |

| 2 | 鲜花 | 15.00 | 15.00 |

| 3 | 甜点 | 12.50 | 12.50 |

| 4 | 玩具 | 45.00 | 45.00 |

| 5 | 钱包 | 195.00 | 195.00 |

+----+--------+----------------+--------+

5 rows in set (0.00 sec)

正确的互换方法如下:

update product as a, product as b set a.original_price=b.price, a.price=b.original_price where a.id=b.id;

执行结果:

mysql> select * from product;

+----+--------+----------------+--------+

| id | name | original_price | price |

+----+--------+----------------+--------+

| 1 | 雪糕 | 5.00 | 3.50 |

| 2 | 鲜花 | 18.00 | 15.00 |

| 3 | 甜点 | 25.00 | 12.50 |

| 4 | 玩具 | 55.00 | 45.00 |

| 5 | 钱包 | 285.00 | 195.00 |

+----+--------+----------------+--------+

5 rows in set (0.00 sec)

mysql> update product as a, product as b set a.original_price=b.price, a.price=b.original_price where a.id=b.id;

Query OK, 5 rows affected (0.01 sec)

Rows matched: 5 Changed: 5 Warnings: 0

mysql> select * from product;

+----+--------+----------------+--------+

| id | name | original_price | price |

+----+--------+----------------+--------+

| 1 | 雪糕 | 3.50 | 5.00 |

| 2 | 鲜花 | 15.00 | 18.00 |

| 3 | 甜点 | 12.50 | 25.00 |

| 4 | 玩具 | 45.00 | 55.00 |

| 5 | 钱包 | 195.00 | 285.00 |

+----+--------+----------------+--------+

5 rows in set (0.00 sec)

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