3种Python检测URL状态

python

需求:Python检测URL状态,并追加保存200的URL

代码一:

python">#! /usr/bin/env python

#coding=utf-8

import sys

import requests

def getHttpStatusCode(url):

try:

request = requests.get(url)

httpStatusCode = request.status_code

return httpStatusCode

except requests.exceptions.HTTPError as e:

return e

if __name__ == "__main__":

with open("1.txt", "r") as f:

for line in f:

try:

status = getHttpStatusCode(line.strip("

"))#换行符

if status == 200:

with open("200.txt","a") as f:

f.write(line + "

")

print line

else:

print "no 200 code"

except Exception as e:

print e

代码二:

#! /usr/bin/env python

# -*--coding:utf-8*-

#Python学习交流群:778463939

import requests

def request_status(line):

conn = requests.get(line)

if conn.status_code == 200:

with open("url_200.txt", "a") as f:

f.write(line + "

")

return line13 else:

return None

if __name__ == "__main__":

with open("/1.txt", "rb") as f:

for line in f:

try:

purge_url = request_status(line.strip("

"))

except Exception as e:

pass

代码三:

#! /usr/bin/env python

#coding:utf-8

import os,urllib,linecache

import sys

result = list()

for x in linecache.updatecache(r"1.txt"):

try:

a = urllib.urlopen(x.replace("/n","")).getcode()

#print x,a

except Exception,e:

print e

if a == 200:

#result.append(x) #保存

#result.sort() #排序结果

#open("2.txt", "w").write("%s" % "

".join(result)) #保存入结果文件

with open ("200urllib.txt","a") as f: ## r只读,w可写,a追加

f.write(x + "

")

else:

print "error"

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