python多线程编程4死锁和可重入锁

Z时代
2024-01-10
分类：综合

python

死锁

在线程间共享多个资源的时候，如果两个线程分别占有一部分资源并且同时等待对方的资源，就会造成死锁。尽管死锁很少发生，但一旦发生就会造成应用的停止响应。下面看一个死锁的例子：

python;toolbar:false;"># encoding: UTF-8
import threading
import time
class MyThread(threading.Thread):
    def do1(self):
        global resA, resB
        if mutexA.acquire():
             msg = self.name+" got resA"
             print msg
             if mutexB.acquire(1):
                 msg = self.name+" got resB"
                 print msg
                 mutexB.release()
             mutexA.release()
    def do2(self):
        global resA, resB
        if mutexB.acquire():
             msg = self.name+" got resB"
             print msg
             if mutexA.acquire(1):
                 msg = self.name+" got resA"
                 print msg
                 mutexA.release()
             mutexB.release()
    def run(self):
        self.do1()
        self.do2()
resA = 0
resB = 0
mutexA = threading.Lock()
mutexB = threading.Lock()
def test():
    for i in range(5):
        t = MyThread()
        t.start()
if __name__ == "__main__":
    test()

执行结果：

Thread-1 got resA

Thread-1 got resB

Thread-1 got resA

Thread-2 got resA

Thread-2 got resB

Thread-2 got resA

Thread-3 got resA

Thread-3 got resB

Thread-3 got resA

Thread-5 got resA

Thread-5 got resB

Thread-4 got resA

此时进程已经死掉。

可重入锁

更简单的死锁情况是一个线程“迭代”请求同一个资源，直接就会造成死锁：

import threading
import time
class MyThread(threading.Thread):
    def run(self):
        global num 
        time.sleep(1)
        if mutex.acquire(1):  
            num = num+1
            msg = self.name+" set num to "+str(num)
            print msg
            mutex.acquire()
            mutex.release()
            mutex.release()
num = 0
mutex = threading.Lock()
def test():
    for i in range(5):
        t = MyThread()
        t.start()
if __name__ == "__main__":
    test()

为了支持在同一线程中多次请求同一资源，python提供了“可重入锁”：threading.RLock。RLock内部维护着一个Lock和一个counter变量，counter记录了acquire的次数，从而使得资源可以被多次require。直到一个线程所有的acquire都被release，其他的线程才能获得资源。上面的例子如果使用RLock代替Lock，则不会发生死锁：

import threading
import time
class MyThread(threading.Thread):
    def run(self):
        global num 
        time.sleep(1)
        if mutex.acquire(1):  
            num = num+1
            msg = self.name+" set num to "+str(num)
            print msg
            mutex.acquire()
            mutex.release()
            mutex.release()
num = 0
mutex = threading.RLock()
def test():
    for i in range(5):
        t = MyThread()
        t.start()
if __name__ == "__main__":
    test()