int整型溢出

  • Z时代
  • 2024-01-10
  • 分类：综合

编程

int最大值和最小值为:

    /**
     * A constant holding the minimum value an {@code int} can
     * have, -2<sup>31</sup>.
     */
    @Native public static final int   MIN_VALUE = 0x80000000;
    /**
     * A constant holding the maximum value an {@code int} can
     * have, 2<sup>31</sup>-1.
     */
    @Native public static final int   MAX_VALUE = 0x7fffffff;

  • 当最大值加上 1 时，结果反而变成表示范围中最小的值

  • 当最小值减上 1 时，结果反而变成表示范围中最大的值

int x = java.lang.Integer.MAX_VALUE;
System.out.println("x = " + x);
System.out.println("x + 1 = " + (x + 1));
System.out.println("x + 3 = " + ((long) x + 3));
System.out.println("--------------");
int y = Integer.MIN_VALUE;
System.out.println("y = " + y);
System.out.println("y - 1 = " + (y - 1));
System.out.println("y - 3 = " + ((long) y - 3));

输出如下：

x = 2147483647
x + 1 = -2147483648
x + 3 = 2147483650
--------------
y = -2147483648
y - 1 = 2147483647
y - 3 = -2147483651

参考链接：

java-int数据的溢出 - 对林风眠 - 博客园

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