python绘制汉诺塔
本文实例为大家分享了python绘制汉诺塔的具体代码,供大家参考,具体内容如下
源码:
import turtle
class Stack:
def __init__(self):
self.items = []
def isEmpty(self):
return len(self.items) == 0
def push(self, item):
self.items.append(item)
def pop(self):
return self.items.pop()
def peek(self):
if not self.isEmpty():
return self.items[len(self.items) - 1]
def size(self):
return len(self.items)
def drawpole_3(): # 画出汉诺塔的poles
t = turtle.Turtle()
t.hideturtle()
def drawpole_1(k):
t.up()
t.pensize(10)
t.speed(100)
t.goto(400 * (k - 1), 100)
t.down()
t.goto(400 * (k - 1), -100)
t.goto(400 * (k - 1) - 20, -100)
t.goto(400 * (k - 1) + 20, -100)
drawpole_1(0) # 画出汉诺塔的poles[0]
drawpole_1(1) # 画出汉诺塔的poles[1]
drawpole_1(2) # 画出汉诺塔的poles[2]
def creat_plates(n): # 制造n个盘子
plates = [turtle.Turtle() for i in range(n)]
for i in range(n):
plates[i].up()
plates[i].hideturtle()
plates[i].shape("square")
plates[i].shapesize(1, 8 - i)
plates[i].goto(-400, -90 + 20 * i)
plates[i].showturtle()
return plates
def pole_stack(): # 制造poles的栈
poles = [Stack() for i in range(3)]
return poles
def moveDisk(plates, poles, fp, tp): # 把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp]
mov = poles[fp].peek()
plates[mov].goto((fp - 1) * 400, 150)
plates[mov].goto((tp - 1) * 400, 150)
l = poles[tp].size() # 确定移动到底部的高度(恰好放在原来最上面的盘子上面)
plates[mov].goto((tp - 1) * 400, -90 + 20 * l)
def moveTower(plates, poles, height, fromPole, toPole, withPole): # 递归放盘子
if height >= 1:
moveTower(plates, poles, height - 1, fromPole, withPole, toPole)
moveDisk(plates, poles, fromPole, toPole)
poles[toPole].push(poles[fromPole].pop())
moveTower(plates, poles, height - 1, withPole, toPole, fromPole)
myscreen = turtle.Screen()
drawpole_3()
n = int(input("请输入汉诺塔的层数并回车:\n"))
plates = creat_plates(n)
poles = pole_stack()
for i in range(n):
poles[0].push(i)
moveTower(plates, poles, n, 0, 2, 1)
myscreen.exitonclick()
效果图:
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