在单个MySQL查询中计算来自不同表的NOT NULL值
要计算来自单独表的值,语法如下:
Select(
select count(yourColumnName) from yourTableName1) as anyAliasName1,
(
select count(yourColumnName) from yourTableName2) as anyAliasName2;
让我们首先创建一个表-
mysql> create table DemoTable1-> (
-> Id int
-> );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable1 values(1);mysql> insert into DemoTable1 values(NULL);
mysql> insert into DemoTable1 values(2);
mysql> insert into DemoTable1 values(3);
使用select语句显示表中的所有记录-
mysql> select * from DemoTable1;
这将产生以下输出-
+------+| Id |
+------+
| 1 |
| NULL |
| 2 |
| 3 |
+------+
4 rows in set (0.00 sec)
以下是创建第二个表的查询-
mysql> create table DemoTable2-> (
-> Id int
-> );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable2 values(10);mysql> insert into DemoTable2 values(NULL);
mysql> insert into DemoTable2 values(NULL);
使用select语句显示表中的所有记录-
mysql> select * from DemoTable2;
这将产生以下输出-
+------+| Id |
+------+
| 10 |
| NULL |
| NULL |
+------+
3 rows in set (0.00 sec)
这是从单独的表中获取计数的查询-
mysql> select-> (
-> select count(Id) from DemoTable1) as CountFirstTableId,
-> (
-> select count(Id) from DemoTable2) as CountSecondTableId
-> ;
这将产生以下输出-
+-------------------+--------------------+| CountFirstTableId | CountSecondTableId |
+-------------------+--------------------+
| 3 | 1 |
+-------------------+--------------------+
1 row in set (0.00 sec)
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