如何使用dplyr包基于R数据帧中的另一列查找列中特定字符串的频率?
当我们在R数据帧中有两个或多个分类列,其中字符串作为类别级别或数字作为字符串/整数时,我们可以找到基于另一个的频率。这将有助于我们识别跨列频率,并且可以了解基于另一列的一个类别的分布。要使用dplyr软件包执行此操作,我们可以使用过滤器功能。
示例
请看以下数据帧-
Group<−sample(1:5,20,replace=TRUE)Standard<−sample(c("I","II","III"),20,replace=TRUE)
df1<−data.frame(Group,Standard)
df1
输出结果
Group Standard1 3 III
2 5 III
3 5 I
4 3 I
5 2 II
6 4 II
7 3 III
8 2 I
9 1 II
10 4 III
11 3 II
12 4 III
13 4 III
14 4 III
15 4 III
16 4 III
17 5 III
18 3 II
19 5 III
20 1 III
查找标准组的频率-
library(dplyr)df1%>%filter(Standard=="I")%>%count(Group)
输出结果
Group n1 2 1
2 3 1
3 5 1
示例
df1%>%filter(Standard=="II")%>%count(Group)
输出结果
Group n1 1 1
2 2 1
3 3 2
4 4 1
示例
df1%>%filter(Standard=="III")%>%count(Group)
输出结果
Group n1 1 1
2 3 2
3 4 6
4 5 3
让我们看另一个例子-
Class<−sample(c("First","Second","Third"),20,replace=TRUE)Gender<−sample(c("Male","Female"),20,replace=TRUE)
df2<−data.frame(Gender,Class)
df2
输出结果
Gender Class1 Female Third
2 Female First
3 Female Second
4 Male Third
5 Male Third
6 Female Second
7 Male First
8 Female Third
9 Female Second
10 Female Second
11 Female First
12 Female Second
13 Male First
14 Female Third
15 Female Third
16 Male Third
17 Male Third
18 Male Second
19 Female Second
20 Male Second
df2%>%filter(Class=="Third")%>%count(Gender)
Gender n
1 Female 4
2 Male 4
df2%>%filter(Class=="First")%>%count(Gender)
Gender n
1 Female 2
2 Male 2
df2%>%filter(Class=="Second")%>%count(Gender)
Gender n
1 Female 6
2 Male 2
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