SpringBoot2 JPA解决懒加载异常的问题

  • Z时代
  • 2024-01-10
  • 分类：综合

jpa解决懒加载异常

在我上一遍文章上进行行修改，SpringBoot2 实现JPA分页和排序分页

实体类上改：

@Entity
@Table(name = "employee")
@JsonIgnoreProperties(value={"hibernateLazyInitializer", "department"})
public class Employee {
 @Id
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 private Integer empId;
 private String lastName;
 private String email;
 @Temporal(TemporalType.DATE)
 private Date birth;
 @Temporal(TemporalType.TIMESTAMP)
 private Date createTime;
 @ManyToOne(fetch = FetchType.LAZY)
 @JoinColumn(name = "dept_id")
 private Department department;
 public Integer getEmpId() {
  return empId;
 }
 public void setEmpId(Integer empId) {
  this.empId = empId;
 }
 public String getLastName() {
  return lastName;
 }
 public void setLastName(String lastName) {
  this.lastName = lastName;
 }
 public String getEmail() {
  return email;
 }
 public void setEmail(String email) {
  this.email = email;
 }
 public Date getBirth() {
  return birth;
 }
 public void setBirth(Date birth) {
  this.birth = birth;
 }
 public Date getCreateTime() {
  return createTime;
 }
 public void setCreateTime(Date createTime) {
  this.createTime = createTime;
 }
 public Department getDepartment() {
  return department;
 }
 public void setDepartment(Department department) {
  this.department = department;
 }
}

控制器验证

import java.util.Iterator;
@RestController
public class EmployeeController {
 @Autowired
 private EmployeeService employeeService;
 @GetMapping("/emp")
 public Page<Employee> showPage(@RequestParam(value = "page") Integer page, @RequestParam(value = "size") Integer size){
  System.out.println("分页： page:"+page+"; size:"+size);
  return employeeService.getPage(page, size);
 }
 @GetMapping("/emp_sort")
 public Page<Employee> showSortPage(@RequestParam(value = "page") Integer page, @RequestParam(value = "size") Integer size){
  System.out.println("排序分页： page:"+page+"; size:"+size);
  Page<Employee> list = employeeService.getPageSort(page, size);
  Iterator<Employee> it=list.iterator();
  while(it.hasNext()){
   System.out.println("value:"+(it.next()).getDepartment().getDeptName());
  }
  return list;
 }
}

我大概实现了一下，具体的如果大佬找到更好的方法或者发现我的方法是错的，希望各位大佬提醒一下！感谢！

补充：SpringBoot jpa 使用懒加载时，报异常：session失效

报异常:

could not initialize proxy - no Session

1、在方法上加@Transactional 注解，失败

2、在application.yml 文件加上jpa.properties.open-in-view: true 失败

3、在ResourceServerApplication.java 启动文件中加上：

 @Bean
 public OpenEntityManagerInViewFilter openEntityManagerInViewFilter() {
   return new OpenEntityManagerInViewFilter();
 }

成功解决~

总结：

要解决no session 问题需要：

配置文件中加jpa.properties.open-in-view: true同时在启动文件中加@Bean

以上为个人经验，希望能给大家一个参考，也希望大家多多支持。如有错误或未考虑完全的地方，望不吝赐教。

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