当MySQL中输入为null时,为date_format返回null?
IF()
当输入在MySQL中为null时,使用函数为date_format返回null。语法如下-
SELECT IF(yourDateColumnName,date_format(yourDateColumnName, '%d/%m/%Y'),NULL) FROM yourTableName;
为了理解上述语法,让我们创建一个表。创建表的查询如下-
mysql> create table returnNullWhenInputIsNullDemo-> (
-> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
-> ShippingDate datetime
-> );
现在,您可以使用insert命令在表中插入一些记录。查询如下-
mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values('2019-01-21');mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values(NULL);
mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values('2018-03-25');
mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values(NULL);
mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values(NULL);
mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values('2012-04-23');
mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values('2018-12-01');
mysql> insert into returnNullWhenInputIsNullDemo(ShippingDate) values('2016-11-13');
使用select语句显示表中的所有记录。查询如下-
mysql> select *from returnNullWhenInputIsNullDemo;
以下是输出-
+----+---------------------+| Id | ShippingDate |
+----+---------------------+
| 1 | 2019-01-21 00:00:00 |
| 2 | NULL |
| 3 | 2018-03-25 00:00:00 |
| 4 | NULL |
| 5 | NULL |
| 6 | 2012-04-23 00:00:00 |
| 7 | 2018-12-01 00:00:00 |
| 8 | 2016-11-13 00:00:00 |
+----+---------------------+
8 rows in set (0.00 sec)
这是在MySQL中输入为null时为date_format返回null的查询-
mysql> SELECT IF(ShippingDate,date_format(ShippingDate, '%d/%m/%Y'),NULL) FROM returnNullWhenInputIsNullDemo;
以下是输出-
+-------------------------------------------------------------+| IF(ShippingDate,date_format(ShippingDate, '%d/%m/%Y'),NULL) |
+-------------------------------------------------------------+
| 21/01/2019 |
| NULL |
| 25/03/2018 |
| NULL |
| NULL |
| 23/04/2012 |
| 01/12/2018 |
| 13/11/2016 |
+-------------------------------------------------------------+
8 rows in set (0.05 sec)
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