C语言指向结构的指针
示例
当变量包含时struct，可以使用点运算符（.）访问其字段。但是，如果您有指向的指针struct，则将无法使用。您必须使用箭头运算符（->）来访问其字段。这是一个使用structs指针并演示了箭头运算符的堆栈的非常简单的示例（有些人会说“可怕而简单”）。
#include <stdlib.h>#include <stdio.h>
/* structs */
struct stack
{
struct node *top;
int size;
};
struct node
{
int data;
struct node *next;
};
/* function declarations */
int push(int, struct stack*);
int pop(struct stack*);
void destroy(struct stack*);
int main(void)
{
int result = EXIT_SUCCESS;
size_t i;
/* allocate memory for a struct stack and record its pointer */
struct stack *stack = malloc(sizeof *stack);
if (NULL == stack)
{
perror("malloc() failed");
return EXIT_FAILURE;
}
/* initialize stack */
stack->top = NULL;
stack->size = 0;
/* push 10 ints */
{
int data = 0;
for(i = 0; i < 10; i++)
{
printf("Pushing: %d\n", data);
if (-1 == push(data, stack))
{
perror("push() failed");
result = EXIT_FAILURE;
break;
}
++data;
}
}
if (EXIT_SUCCESS == result)
{
/* pop 5 ints */
for(i = 0; i < 5; i++)
{
printf("Popped: %i\n", pop(stack));
}
}
/* destroy stack */
destroy(stack);
return result;
}
/* Push a value onto the stack. */
/* Returns 0 on success and -1 on failure. */
int push(int data, struct stack *stack)
{
int result = 0;
/* allocate memory for new node */
struct node *new_node = malloc(sizeof *new_node);
if (NULL == new_node)
{
result = -1;
}
else
{
new_node->data = data;
new_node->next = stack->top;
stack->top = new_node;
stack->size++;
}
return result;
}
/* Pop a value off of the stack. */
/* Returns the value popped off the stack */
int pop(struct stack *stack)
{
struct node *top = stack->top;
int data = top->data;
stack->top = top->next;
stack->size--;
free(top);
return data;
}
/* destroy the stack */
void destroy(struct stack *stack)
{
/* free all pointers */
while(stack->top != NULL)
{
pop(stack);
}
}
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