C# 获取当前年份的周期及周期所在日期范围(推荐)

最近有一个项目要用到年份周期,用于数据统计图表展示使用,当中用到年份周期,以及年份周期所在的日期范围。当初设想通过已知数据来换算年份周期,经过搜索资料发现通过数据库SQL语句来做,反而更加复杂。现在改变思路通过C#后台代码来算出两段日期范围中年份周期,在依据年份周期所对应的日期范围进行数据库查询进行统计。需要解决以下两个点问题,

第一点:依据日期查找所在年份的第几周;

第二点:依据年份所在的周期计算出周期所在的日期范围。

using System;

using System.Collections.Generic;

using System.Globalization;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

namespace ConsoleApplication6

{

class Program

{

static void Main(string[] args)

{

GregorianCalendar gc = new GregorianCalendar();

int weekOfYear = gc.GetWeekOfYear(DateTime.Now, CalendarWeekRule.FirstDay, DayOfWeek.Monday);

Console.WriteLine("当前第{0}周", weekOfYear);

DateTime startDate, lastDate;

for (int i = 1; i <= 53; i++)

{

GetDaysOfWeeks(DateTime.Now.Year, i, out startDate, out lastDate);

Console.WriteLine("第{0}周", i);

Console.WriteLine(startDate);

Console.WriteLine(lastDate);

}

Console.ReadLine();

}

public static bool GetDaysOfWeeks(int year, int index, out DateTime first, out DateTime last)

{

first = DateTime.MinValue;

last = DateTime.MinValue;

if (year < 1700 || year > 9999)

{

//"年份超限"

return false;

}

if (index < 1 || index > 53)

{

//"周数错误"

return false;

}

DateTime startDay = new DateTime(year, 1, 1); //该年第一天

DateTime endDay = new DateTime(year + 1, 1, 1).AddMilliseconds(-1);

int dayOfWeek = 0;

if (Convert.ToInt32(startDay.DayOfWeek.ToString("d")) > 0)

dayOfWeek = Convert.ToInt32(startDay.DayOfWeek.ToString("d")); //该年第一天为星期几

if (dayOfWeek == 0) { dayOfWeek = 7; }

if (index == 1)

{

first = startDay.AddDays(7 - dayOfWeek - 6);

if (dayOfWeek == 6)

{

last = first;

}

else

{

last = startDay.AddDays((7 - dayOfWeek));

}

}

else

{

first = startDay.AddDays((8 - dayOfWeek) + (index - 2) * 7); //index周的起始日期

last = first.AddDays(6);

//if (last > endDay)

//{

// last = endDay;

//}

}

if (first > endDay) //startDayOfWeeks不在该年范围内

{

//"输入周数大于本年最大周数";

return false;

}

return true;

}

}

}

  执行结果 

总结

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