首先在最近3个月内订购,然后在MySQL中按字母顺序订购?
让我们首先创建一个表-
mysql> create table DemoTable1526-> (
-> CustomerName varchar(20),
-> PurchaseDate date
-> );
使用insert命令在表中插入一些记录。在这里,我们插入了2019年的日期-
mysql> insert into DemoTable1526 values('Adam','2019-06-01');mysql> insert into DemoTable1526 values('Sam','2019-04-26');
mysql> insert into DemoTable1526 values('Chris','2019-05-24');
mysql> insert into DemoTable1526 values('David','2019-10-10');
mysql> insert into DemoTable1526 values('Bob','2019-12-31');
使用select语句显示表中的所有记录-
mysql> select * from DemoTable1526;
这将产生以下输出-
+--------------+--------------+| CustomerName | PurchaseDate |
+--------------+--------------+
| Adam | 2019-06-01 |
| Sam | 2019-04-26 |
| Chris | 2019-05-24 |
| David | 2019-10-10 |
| Bob | 2019-12-31 |
+--------------+--------------+
5 rows in set (0.00 sec)
当前日期如下-
mysql> select curdate();+------------+
| curdate() |
+------------+
| 2019-10-08 |
+------------+
1 row in set (0.00 sec)
这是要在2019年的最后3个月之前订购的查询,然后按字母顺序-
mysql> select * from DemoTable1526-> order by PurchaseDate > curdate() - interval 3 month desc,CustomerName;
这将产生以下输出-
+--------------+--------------+| CustomerName | PurchaseDate |
+--------------+--------------+
| Bob | 2019-12-31 |
| David | 2019-10-10 |
| Adam | 2019-06-01 |
| Chris | 2019-05-24 |
| Sam | 2019-04-26 |
+--------------+--------------+
5 rows in set (0.00 sec)
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