如何编写一个MySQL存储函数来更新表中的值？
众所周知，要返回结果时最好使用该函数。因此，当我们将创建用于操作表的存储函数（如“插入”或“更新”值）时，它或多或少类似于存储过程。在以下示例中，我们将创建一个名为“ tbl_update”的存储函数，该函数将更新名为“ student_marks”的表中的值。
mysql> Select * from student_marks//+---------+------+---------+---------+---------+
| Name | Math | English | Science | History |
+---------+------+---------+---------+---------+
| Raman | 95 | 89 | 85 | 81 |
| Rahul | 90 | 87 | 86 | 81 |
| Mohit | 90 | 85 | 86 | 81 |
| Saurabh | NULL | NULL | NULL | NULL |
+---------+------+---------+---------+---------+
4 rows in set (0.00 sec)
mysql> Create Function tbl_Update(S_name Varchar(50),M1 INT,M2 INT,M3 INT,M4 INT)
-> RETURNS INT
-> DETERMINISTIC
-> BEGIN
-> UPDATE student_marks SET Math = M1,English = M2, Science = M3, History =M4 WHERE Name = S_name;
-> RETURN 1;
-> END //
mysql> Select tbl_update('Saurabh',85,69,75,82);
+------------------------------------+
| tbl_update('Saurabh',85,69,75,82) |
+------------------------------------+
| 1 |
+------------------------------------+
1 row in set (0.07 sec)
mysql> Select * from Student_marks;
+---------+------+---------+---------+---------+
| Name | Math | English | Science | History |
+---------+------+---------+---------+---------+
| Raman | 95 | 89 | 85 | 81 |
| Rahul | 90 | 87 | 86 | 81 |
| Mohit | 90 | 85 | 86 | 81 |
| Saurabh | 85 | 69 | 75 | 82 |
+---------+------+---------+---------+---------+
4 rows in set (0.00 sec)
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