C ++ STL中的stack :: empty()函数
原型:
stack<T> st; //声明st.empty();
参数:
No parameter passed
返回类型:布尔型(True或False)
正确:堆栈为空
False:堆栈不为空
包含的头文件:
#include <iostream>#include <stack>
OR
#include <bits/stdc++.h>
用法:
该函数检查堆栈是否为空。
时间复杂度:O(1)
示例
For a stack of integer,stack<int> st;
st.push(4);
st.push(5);
stack content:
5 <-- TOP
4
IF (st.empty())
Print "Stack is empty"
Else
Print "Stack is not empty"
Output:
Prints "Stack is not empty"
st.pop()
st.pop()
Stack content:
Empty stack
IF (st.empty())
Print "Stack is empty"
Else
Print "Stack is not empty"
Output:
Prints "Stack is empty"
C ++实现:
#include <bits/stdc++.h>using namespace std;
int main(){
cout<<"...use of empty function...\n";
int count=0;
stack<int> st; //声明栈
st.push(4); //推4-
st.push(5); //推5-
st.push(6);
cout<<"stack elements are:\n";
while(!st.empty()){//堆栈不为空
cout<<"top element is:"<<st.top()<<endl;//打印顶部元素
st.pop();
count++;
}
if(st.empty()) //检查是否有空堆栈
cout<<"stack empty\n";
cout<<count<<" pop operation performed total to make stack empty\n";
return 0;
}
输出结果
...use of empty function...stack elements are:
top element is:6
top element is:5
top element is:4
stack empty
3 pop operation performed total to make stack empty
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