用C语言公式计算利息金额
问题
编写一个 C 程序来计算几年后增加的存款金额和利息
解决方案
计算利息的公式是 -
M=((r/100) * t);A=P*exp(M);
其中 r= 利率
t=否。年
P=存入金额
M=临时变量
A = 利息后的最终金额
算法
STARTStep 1: declare double variables
Step 2: read amount to be deposited
Step 3: read rate of interest
Step 4: read years you want to deposit
Step 5: Calculate final amount with interest
I. M=((r/100) * t);
II. A=P*exp(M);
Step 6: Print final amount
STOP
示例
#include<stdio.h>输出结果#include<math.h>
#include<ctype.h>
int main(){
double P,r,t,A,M;
printf("存入银行的金额: ");
scanf("%lf",&P);
printf("\n enter the rate of interest:");
scanf("%lf",&r);
printf("\n How many years you want to deposit:");
scanf("%lf",&t);
M=((r/100) * t);
A=P*exp(M);
printf("\n amount after %0.1lf years with interest is:%0.2lf",t,A);
return 0;
}
存入银行的金额: 50000enter the rate of interest:6.5
How many years you want to deposit:5
amount after 5.0 years with interest is:69201.53
以上是 用C语言公式计算利息金额 的全部内容, 来源链接: utcz.com/z/317425.html