MySQL查询以计算日期并获取重复的日期
要显示计数,请使用聚合函数COUNT(*)。让我们首先创建一个表-
create table DemoTable1321-> (
-> ArrivalDatetime timestamp
-> );
示例
使用插入命令在表中插入一些记录-
insert into DemoTable1321 values(now());insert into DemoTable1321 values('2019-01-10 12:34:00');
insert into DemoTable1321 values('2019-06-12 11:34:00');
insert into DemoTable1321 values('2019-06-12 04:50:00');
insert into DemoTable1321 values('2019-09-18 10:50:45');
insert into DemoTable1321 values('2019-06-12 06:10:20');
使用select语句显示表中的所有记录-
select * from DemoTable1321;
输出结果
+---------------------+| ArrivalDatetime |
+---------------------+
| 2019-09-18 21:49:17 |
| 2019-01-10 12:34:00 |
| 2019-06-12 11:34:00 |
| 2019-06-12 04:50:00 |
| 2019-09-18 10:50:45 |
| 2019-06-12 06:10:20 |
+---------------------+
6 rows in set (0.00 sec)
示例
以下是计算日期的查询-
select date(ArrivalDatetime) as OnlyDate,count(*) as Total from DemoTable1321-> group by date(ArrivalDatetime)
-> order by date(ArrivalDatetime);
输出结果
+------------+-------+| OnlyDate | Total |
+------------+-------+
| 2019-01-10 | 1 |
| 2019-06-12 | 3 |
| 2019-09-18 | 2 |
+------------+-------+
3 rows in set (0.00 sec)
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