如何在Java中发送Https Post请求
我想从Java代码登录到应用程序。这是我的代码…
String httpsURL = "https://www.abcd.com/auth/login/";String query = "email="+URLEncoder.encode("abc@xyz.com","UTF-8");
query += "&";
query += "password="+URLEncoder.encode("abcd","UTF-8") ;
URL myurl = new URL(httpsURL);
HttpsURLConnection con = (HttpsURLConnection)myurl.openConnection();
con.setRequestMethod("POST");
con.setRequestProperty("Content-length", String.valueOf(query.length()));
con.setRequestProperty("Content-Type","application/x-www- form-urlencoded");
con.setRequestProperty("User-Agent", "Mozilla/4.0 (compatible; MSIE 5.0;Windows98;DigExt)");
con.setDoOutput(true);
con.setDoInput(true);
DataOutputStream output = new DataOutputStream(con.getOutputStream());
output.writeBytes(query);
output.close();
DataInputStream input = new DataInputStream( con.getInputStream() );
for( int c = input.read(); c != -1; c = input.read() )
System.out.print( (char)c );
input.close();
System.out.println("Resp Code:"+con .getResponseCode());
System.out.println("Resp Message:"+ con .getResponseMessage());
但我无法登录,它只返回登录页面。
如果有人可以,请帮助我了解我在做什么错。
回答:
错误 中间有多余的空格)
con.setRequestProperty("Content-Type","application/x-www- form-urlencoded");
正确
con.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
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