SQL Server相当于MySQL中的substring_index函数

我正在尝试将查询从MySQL移植到SQL SERVER2012。

如何为MySQL的substring_index()编写等效项?

MySQL SUBSTRING_INDEX()从给定字符串中返回指定次数的分隔符之前的子字符串。

SUBSTRING_INDEX(str,delim,count)

SELECT SUBSTRING_INDEX('www.somewebsite.com','.',2);

输出: 'www.somewebsite'

回答:

尝试基于T-SQL和XQuery((root/row)[position() <= sql:variable("@count")])的以下解决方案:

CREATE FUNCTION dbo.SUBSTRING_INDEX

(

@str NVARCHAR(4000),

@delim NVARCHAR(1),

@count INT

)

RETURNS NVARCHAR(4000)

WITH SCHEMABINDING

BEGIN

DECLARE @XmlSourceString XML;

SET @XmlSourceString = (SELECT N'<root><row>' + REPLACE( (SELECT @str AS '*' FOR XML PATH('')) , @delim, N'</row><row>' ) + N'</row></root>');

RETURN STUFF

(

((

SELECT @delim + x.XmlCol.value(N'(text())[1]', N'NVARCHAR(4000)') AS '*'

FROM @XmlSourceString.nodes(N'(root/row)[position() <= sql:variable("@count")]') x(XmlCol)

FOR XML PATH(N''), TYPE

).value(N'.', N'NVARCHAR(4000)')),

1, 1, N''

);

END

GO

SELECT dbo.SUBSTRING_INDEX(N'www.somewebsite.com', N'.', 2) AS Result;

输出:

/*

Result

---------------

www.somewebsite

*/

要么

CREATE FUNCTION dbo.SUBSTRING_INDEX

(

@str NVARCHAR(4000),

@delim NVARCHAR(1),

@count INT

)

RETURNS TABLE

AS

RETURN

WITH Base

AS

(

SELECT XmlSourceString = CONVERT(XML, (SELECT N'<root><row>' + REPLACE( (SELECT @str AS '*' FOR XML PATH('')) , @delim, N'</row><row>' ) + N'</row></root>'))

)

SELECT STUFF

(

((

SELECT @delim + x.XmlCol.value(N'(text())[1]', N'NVARCHAR(4000)') AS '*'

FROM Base b

CROSS APPLY b.XmlSourceString.nodes(N'(root/row)[position() <= sql:variable("@count")]') x(XmlCol)

FOR XML PATH(N''), TYPE

).value(N'.', N'NVARCHAR(4000)')),

1, 1, N''

) AS Result;

GO

SELECT *

FROM (

SELECT N'www.somewebsite.com' UNION ALL

SELECT N'www.yahoo.com' UNION ALL

SELECT N'www.outlook.com'

) a(Value)

CROSS APPLY dbo.SUBSTRING_INDEX(a.Value, N'.', 2) b;

输出:

/*

Value Result

------------------- ---------------

www.somewebsite.com www.somewebsite

www.yahoo.com www.yahoo

www.outlook.com www.outlook

*/

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