如何从python中的线程获取返回值?

foo下面的函数返回一个字符串'foo'。我如何获取'foo'从线程目标返回的值?

from threading import Thread

def foo(bar):

print('hello {}'.format(bar))

return 'foo'

thread = Thread(target=foo, args=('world!',))

thread.start()

return_value = thread.join()

上面显示的“一种显而易见的方法”不起作用:thread.join()return None

回答:

我见过的一种方法是将可变对象(例如列表或字典)与索引或某种其他标识符一起传递给线程的构造函数。然后,线程可以将其结果存储在该对象的专用插槽中。例如:

def foo(bar, result, index):

print 'hello {0}'.format(bar)

result[index] = "foo"

from threading import Thread

threads = [None] * 10

results = [None] * 10

for i in range(len(threads)):

threads[i] = Thread(target=foo, args=('world!', results, i))

threads[i].start()

# do some other stuff

for i in range(len(threads)):

threads[i].join()

print " ".join(results) # what sound does a metasyntactic locomotive make?

如果你确实想join()返回被调用函数的返回值,则可以使用如下所示的Thread子类来实现:

from threading import Thread

def foo(bar):

print 'hello {0}'.format(bar)

return "foo"

class ThreadWithReturnValue(Thread):

def __init__(self, group=None, target=None, name=None,

args=(), kwargs={}, Verbose=None):

Thread.__init__(self, group, target, name, args, kwargs, Verbose)

self._return = None

def run(self):

if self._Thread__target is not None:

self._return = self._Thread__target(*self._Thread__args,

**self._Thread__kwargs)

def join(self):

Thread.join(self)

return self._return

twrv = ThreadWithReturnValue(target=foo, args=('world!',))

twrv.start()

print twrv.join() # prints foo

由于名称修改,这有点麻烦,并且它访问特定于Thread实现的“私有”数据结构…但是它可以工作。

对于python3

class ThreadWithReturnValue(Thread):

def __init__(self, group=None, target=None, name=None,

args=(), kwargs={}, Verbose=None):

Thread.__init__(self, group, target, name, args, kwargs)

self._return = None

def run(self):

print(type(self._target))

if self._target is not None:

self._return = self._target(*self._args,

**self._kwargs)

def join(self, *args):

Thread.join(self, *args)

return self._return

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