如何使用Java解码/解密MD5加密

我正在使用ExtJS框架。我在 有MD5函数来加密某些JSON。我的后端使用Java,所以我想知道如何使用 解密MD5 Javascript加密?

这是我正在使用的MD5函数的JS等效项:

Ext.util.MD5 = function(s,raw,hexcase,chrsz) {

raw = raw || false;

hexcase = hexcase || false;

chrsz = chrsz || 8;

function safe_add(x, y){

var lsw = (x & 0xFFFF) + (y & 0xFFFF);

var msw = (x >> 16) + (y >> 16) + (lsw >> 16);

return (msw << 16) | (lsw & 0xFFFF);

}

function bit_rol(num, cnt){

return (num << cnt) | (num >>> (32 - cnt));

}

function md5_cmn(q, a, b, x, s, t){

return safe_add(bit_rol(safe_add(safe_add(a, q), safe_add(x, t)), s),b);

}

function md5_ff(a, b, c, d, x, s, t){

return md5_cmn((b & c) | ((~b) & d), a, b, x, s, t);

}

function md5_gg(a, b, c, d, x, s, t){

return md5_cmn((b & d) | (c & (~d)), a, b, x, s, t);

}

function md5_hh(a, b, c, d, x, s, t){

return md5_cmn(b ^ c ^ d, a, b, x, s, t);

}

function md5_ii(a, b, c, d, x, s, t){

return md5_cmn(c ^ (b | (~d)), a, b, x, s, t);

}

function core_md5(x, len){

x[len >> 5] |= 0x80 << ((len) % 32);

x[(((len + 64) >>> 9) << 4) + 14] = len;

var a = 1732584193;

var b = -271733879;

var c = -1732584194;

var d = 271733878;

for(var i = 0; i < x.length; i += 16){

var olda = a;

var oldb = b;

var oldc = c;

var oldd = d;

a = md5_ff(a, b, c, d, x[i+ 0], 7 , -680876936);

d = md5_ff(d, a, b, c, x[i+ 1], 12, -389564586);

c = md5_ff(c, d, a, b, x[i+ 2], 17, 606105819);

b = md5_ff(b, c, d, a, x[i+ 3], 22, -1044525330);

a = md5_ff(a, b, c, d, x[i+ 4], 7 , -176418897);

d = md5_ff(d, a, b, c, x[i+ 5], 12, 1200080426);

c = md5_ff(c, d, a, b, x[i+ 6], 17, -1473231341);

b = md5_ff(b, c, d, a, x[i+ 7], 22, -45705983);

a = md5_ff(a, b, c, d, x[i+ 8], 7 , 1770035416);

d = md5_ff(d, a, b, c, x[i+ 9], 12, -1958414417);

c = md5_ff(c, d, a, b, x[i+10], 17, -42063);

b = md5_ff(b, c, d, a, x[i+11], 22, -1990404162);

a = md5_ff(a, b, c, d, x[i+12], 7 , 1804603682);

d = md5_ff(d, a, b, c, x[i+13], 12, -40341101);

c = md5_ff(c, d, a, b, x[i+14], 17, -1502002290);

b = md5_ff(b, c, d, a, x[i+15], 22, 1236535329);

a = md5_gg(a, b, c, d, x[i+ 1], 5 , -165796510);

d = md5_gg(d, a, b, c, x[i+ 6], 9 , -1069501632);

c = md5_gg(c, d, a, b, x[i+11], 14, 643717713);

b = md5_gg(b, c, d, a, x[i+ 0], 20, -373897302);

a = md5_gg(a, b, c, d, x[i+ 5], 5 , -701558691);

d = md5_gg(d, a, b, c, x[i+10], 9 , 38016083);

c = md5_gg(c, d, a, b, x[i+15], 14, -660478335);

b = md5_gg(b, c, d, a, x[i+ 4], 20, -405537848);

a = md5_gg(a, b, c, d, x[i+ 9], 5 , 568446438);

d = md5_gg(d, a, b, c, x[i+14], 9 , -1019803690);

c = md5_gg(c, d, a, b, x[i+ 3], 14, -187363961);

b = md5_gg(b, c, d, a, x[i+ 8], 20, 1163531501);

a = md5_gg(a, b, c, d, x[i+13], 5 , -1444681467);

d = md5_gg(d, a, b, c, x[i+ 2], 9 , -51403784);

c = md5_gg(c, d, a, b, x[i+ 7], 14, 1735328473);

b = md5_gg(b, c, d, a, x[i+12], 20, -1926607734);

a = md5_hh(a, b, c, d, x[i+ 5], 4 , -378558);

d = md5_hh(d, a, b, c, x[i+ 8], 11, -2022574463);

c = md5_hh(c, d, a, b, x[i+11], 16, 1839030562);

b = md5_hh(b, c, d, a, x[i+14], 23, -35309556);

a = md5_hh(a, b, c, d, x[i+ 1], 4 , -1530992060);

d = md5_hh(d, a, b, c, x[i+ 4], 11, 1272893353);

c = md5_hh(c, d, a, b, x[i+ 7], 16, -155497632);

b = md5_hh(b, c, d, a, x[i+10], 23, -1094730640);

a = md5_hh(a, b, c, d, x[i+13], 4 , 681279174);

d = md5_hh(d, a, b, c, x[i+ 0], 11, -358537222);

c = md5_hh(c, d, a, b, x[i+ 3], 16, -722521979);

b = md5_hh(b, c, d, a, x[i+ 6], 23, 76029189);

a = md5_hh(a, b, c, d, x[i+ 9], 4 , -640364487);

d = md5_hh(d, a, b, c, x[i+12], 11, -421815835);

c = md5_hh(c, d, a, b, x[i+15], 16, 530742520);

b = md5_hh(b, c, d, a, x[i+ 2], 23, -995338651);

a = md5_ii(a, b, c, d, x[i+ 0], 6 , -198630844);

d = md5_ii(d, a, b, c, x[i+ 7], 10, 1126891415);

c = md5_ii(c, d, a, b, x[i+14], 15, -1416354905);

b = md5_ii(b, c, d, a, x[i+ 5], 21, -57434055);

a = md5_ii(a, b, c, d, x[i+12], 6 , 1700485571);

d = md5_ii(d, a, b, c, x[i+ 3], 10, -1894986606);

c = md5_ii(c, d, a, b, x[i+10], 15, -1051523);

b = md5_ii(b, c, d, a, x[i+ 1], 21, -2054922799);

a = md5_ii(a, b, c, d, x[i+ 8], 6 , 1873313359);

d = md5_ii(d, a, b, c, x[i+15], 10, -30611744);

c = md5_ii(c, d, a, b, x[i+ 6], 15, -1560198380);

b = md5_ii(b, c, d, a, x[i+13], 21, 1309151649);

a = md5_ii(a, b, c, d, x[i+ 4], 6 , -145523070);

d = md5_ii(d, a, b, c, x[i+11], 10, -1120210379);

c = md5_ii(c, d, a, b, x[i+ 2], 15, 718787259);

b = md5_ii(b, c, d, a, x[i+ 9], 21, -343485551);

a = safe_add(a, olda);

b = safe_add(b, oldb);

c = safe_add(c, oldc);

d = safe_add(d, oldd);

}

return [a, b, c, d];

}

function str2binl(str){

var bin = [];

var mask = (1 << chrsz) - 1;

for(var i = 0; i < str.length * chrsz; i += chrsz) {

bin[i>>5] |= (str.charCodeAt(i / chrsz) & mask) << (i%32);

}

return bin;

}

function binl2str(bin){

var str = "";

var mask = (1 << chrsz) - 1;

for(var i = 0; i < bin.length * 32; i += chrsz) {

str += String.fromCharCode((bin[i>>5] >>> (i % 32)) & mask);

}

return str;

}

function binl2hex(binarray){

var hex_tab = hexcase ? "0123456789ABCDEF" : "0123456789abcdef";

var str = "";

for(var i = 0; i < binarray.length * 4; i++) {

str += hex_tab.charAt((binarray[i>>2] >> ((i%4)*8+4)) & 0xF) + hex_tab.charAt((binarray[i>>2] >> ((i%4)*8 )) & 0xF);

}

return str;

}

return (raw ? binl2str(core_md5(str2binl(s), s.length * chrsz)) : binl2hex(core_md5(str2binl(s), s.length * chrsz)) );

};

回答:

MD5是 哈希

(即单向转换),因此您无法对其进行解密。您可以将已知哈希与从明文计算出的哈希进行比较,以验证输入的有效性。Java已经为此内置了库。我在下面使用了此代码,可以根据需要进行调整,还请验证您在javascript中生成的哈希具有相同的编码。

import java.security.MessageDigest;    

import sun.misc.BASE64Encoder;

public class MD5Sample {

/**

* Cipher for encode

*/

private final MessageDigest md;

public MD5Sample() throws SecurityException {

try {

md = MessageDigest.getInstance("MD5", "SUN");

}catch(Exception se) {

throw new SecurityException("In MD5 constructor " + se);

}

}

public String encode(String in) throws Exception {

if (in == null) {

return null;

}

try {

byte[] raw = null;

byte[] stringBytes = null;

stringBytes = in.getBytes("UTF8");

synchronized(md) {

raw = md.digest(stringBytes);

}

BASE64Encoder encoder = new BASE64Encoder();

return encoder.encode(raw);

} catch (Exception se) {

throw new Exception("Exception while encoding " + se);

}

}

public String decode(String in) {

throw new RuntimeException("NOT SUPPORTED");

}

/**

* Test harness

* @param args

*/

public static void main(String[] args) {

String clearText = "apple";

try {

MD5Sample app = new MD5Sample();

String encryptedHash = app.encode(clearText);

System.out.println(encryptedHash);

} catch (Exception e) {

e.printStackTrace();

}

}

}

以上是 如何使用Java解码/解密MD5加密 的全部内容, 来源链接: utcz.com/qa/435139.html

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