Node.JS readFileSync（）函数

Z时代
2024-01-10
分类：问答

index.js

var server = require("./server");
var router = require("./router");
server.start(router.route);

server.js

//Script to start a server
var http = require("http");
var url = require("url");
var fs = require("fs");
function start(route) {
    function onRequest(request, response) {
        var pathname = url.parse(request.url).pathname;
        route(pathname, response, fs);
    }
    http.createServer(onRequest).listen(8888);
    console.log("Server has started.");
}
exports.start = start;

router.js

function route(pathname, response, fs) {
    var regex = new RegExp('^/view/?$');
    var directpath = "D:/nodejs/file_upload" + pathname;
    var voo = fs.readFileSync(directpath);
    if(regex.test(pathname)){
        response.writeHead(200, {"Content-Type": "text/html"});
        console.log("About to route a request for " + pathname);
        response.end(voo);
    } else{
        response.writeHead(404);
        response.end("<br/>404, file not found");
    }
}
exports.route = route;

index.html

<!DOCTYPE html>
<html>
    <body>
        <p>Hello My friend </p>
    </body>
</html>

我正在尝试将文件路径存储在变量中，然后通过readFileSync（）函数将其提供给我，但这在控制台中给了我错误提示。

Error: EISDIR, illegal operation on a directory
    at Object.fs.readSync (fs.js:487:19)
    at Object.fs.readFileSync (fs.js:326:28)
    at route (D:\nodejs\file_upload\router.js:7:15)
    at Server.onRequest (D:\nodejs\file_upload\server.js:15:6)
    at Server.emit (events.js:98:17)
    at HTTPParser.parser.onIncoming (http.js:2108:12)
    at HTTPParser.parserOnHeadersComplete [as onHeadersComplete] (http.js:121:23
)
    at Socket.socket.ondata (http.js:1966:22)
    at TCP.onread (net.js:527:27)

但是如果我直接在函数中输入路径“ D：/nodejs/file_upload/view/index.html”，那么它将在浏览器中显示该页面。

我将index.html文件存储在视图文件夹中